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daser333 [38]
4 years ago
7

HELPPPP IMA GIVE BRAINLIST

Mathematics
1 answer:
Crazy boy [7]4 years ago
6 0

Answer:  41%

Step-by-step explanation: Look at the prime numbers [2,3,5,7,11] and Add the amounts below them. (3+6 +11 +16 +5 = 41)

Then add up all the other amounts (this turns out to be 59, so the total rolls =100)

41/100   No calculator needed!

You might be interested in
What is the 15th term of the sequence an = -2n(n 3)?
Hoochie [10]
An = -2n(n + 3)
a(15) = -2(15)(15 + 3) = -30(18) = -540
5 0
3 years ago
Please help!
Papessa [141]

Answer:

x = 1 and x = 2

x = 4 and x = -4

Step-by-step explanation:

Vertical asymptotes appear where the function does not have a value. This is most commonly when the denominator of a rational function is 0. Find the asymptotes by factoring the denominator and setting it equal to 0. Then solve for x.

<u>First equation</u>

x² - 3x + 2 factors into (x-1)(x-2)

When x-1 = 0, x = 1. When x-2=0, x = 2. The V.A. are at x = 1 and x = 2.

<u>Second equation</u>

x²  - 16 factors into (x+4)(x-4)

When x+4= 0, x = -4. When x-4 = 0, then x = 4. The V.A. are at x = -4 and x = 4.

6 0
3 years ago
Read 2 more answers
The Highway Safety Department wants to study the driving habits of individuals. A sample of 32 cars traveling on the highway rev
GarryVolchara [31]

Answer:

n=126

Step-by-step explanation:

Data given and previous concepts

\bar X=60 represent the sample mean

s=11 represent the sample deviation

n=32 represent the sample size

Confidence =0.95 or 95%

\alpha =1-0.95=0.05 represent the significance level

ME= 2 represent the margin of error required

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

Assuming the X follows a normal distribution

X \sim N(\mu, \sigma)

Solution to the problem

Since we don't have the population deviation. We know that the margin of error for a confidence interval is given by:

Me=t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

The next step would be find the value of \t_{\alpha/2}, \alpha=1-0.95=0.05 and \alpha/2=0.025. The degrees of freedom are given by:

df=n-1=32-1=31

Using the normal standard table, excel or a calculator we see that:

t_{\alpha/2}=2.04

And the code in excel is this one:  "=T.INV(1-0.025,31)"

If we solve for n from formula (1) we got:

\sqrt{n}=\frac{t_{\alpha/2} s}{Me}

n=(\frac{t_{\alpha/2} s}{Me})^2

And we have everything to replace into the formula:

n=(\frac{2.04(11)}{2})^2 =125.88

And if we round up the answer we see that the value of n to ensure the margin of error required \pm=2 miles is n=126.

3 0
3 years ago
Brad operates a storage business on the accrual method. On July 1 Brad paid $48,000 for rent on his storage warehouse and $18,00
weqwewe [10]

Answer:

B. $24,000 for the rent and $18,000 for the insurance.

Step-by-step explanation:

Accrual method is a way of recording accounting transactions for revenue based on the time when they are earned and when the expenses are incurred.

Here, in the given scenario, $24,000 is accrued or $2000 per month is accrued.

The payment for insurance or rent spans for 2 time periods. That is six  months this year and six months next year.

We know that insurance is a type of payment liability and accrues only when its paid.

So, he answer here will be option B.

7 0
3 years ago
Please help me. Thank you so much
Olegator [25]
Is this for a test or assignment ? I like to know if I should give an expansion to the answer or not
7 0
3 years ago
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