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Travka [436]
3 years ago
10

How do I solve system of equations by substitution 3x-7y=41 x=-2y-21

Mathematics
2 answers:
Butoxors [25]3 years ago
8 0

Answer:

(-5;-8)

Step-by-step explanation:

-6y-63-7y=41

-13y=104

y=-8

x=-2*-8-21=-5

Rashid [163]3 years ago
5 0
Going off the value of x in terms of y given in the second equation, we can substitute the x in the first equation with the value -2y - 21 to give us the equation

3(-2y - 21) - 7y = 41

Distributing the 3 to the -2y and -12:

-6y - 63 -7y = 41

Combining like terms:

-13y - 63 = 41

Adding 63 to either side:

-13y = 104

And dividing both sides by -13:

y = -8

We can plug in this solution for y to the second equation to obtain a solution for x:

x = -2(-8) - 21
x = 16 - 21
x = -5

So our solution is the pair (-5, -8).
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Answer:

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3. t=4

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Step-by-step explanation:

1. 5m+4=7m+6

5m-7m=6-5

2m=1

m=1/2

2. -5x+3=2x-1

-5x-2x=-1-3

-7x=-4

x= -4/-7= 4/7

3. 5t-3=3t+5

5t-3t=5+3

2t=8

t=8/2= 4

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2 years ago
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PLEASE HELP ME I'M GIVING 20PTS AND MARKING BRAINLIEST!!!!
pishuonlain [190]

Using a trigonometric identity, it is found that the values of the cosine and the tangent of the angle are given by:

  • \cos{\theta} = \pm \frac{2\sqrt{2}}{3}
  • \tan{\theta} = \pm \frac{\sqrt{2}}{4}

<h3>What is the trigonometric identity using in this problem?</h3>

The identity that relates the sine squared and the cosine squared of the angle, as follows:

\sin^{2}{\theta} + \cos^{2}{\theta} = 1

In this problem, we have that the sine is given by:

\sin{\theta} = \frac{1}{3}

Hence, applying the identity, the cosine is given as follows:

\cos^2{\theta} = 1 - \sin^2{\theta}

\cos^2{\theta} = 1 - \left(\frac{1}{3}\right)^2

\cos^2{\theta} = 1 - \frac{1}{9}

\cos^2{\theta} = \frac{8}{9}

\cos{\theta} = \pm \sqrt{\frac{8}{9}}

\cos{\theta} = \pm \frac{2\sqrt{2}}{3}

The tangent is given by the sine divided by the cosine, hence:

\tan{\theta} = \frac{\sin{\theta}}{\cos{\theta}}

\tan{\theta} = \frac{\frac{1}{3}}{\pm \frac{2\sqrt{2}}{3}}

\tan{\theta} = \pm \frac{1}{2\sqrt{2}} \times \frac{\sqrt{2}}{\sqrt{2}}

\tan{\theta} = \pm \frac{\sqrt{2}}{4}

More can be learned about trigonometric identities at brainly.com/question/24496175

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5 0
1 year ago
Last month, customers at a gift shop bought 40 birthday cards,
Iteru [2.4K]

Answer:

32 People

Step-by-step explanation:

I put 40 (Number of birthday cards bought previously) over 125 (Number of expected costumers) and multiplied it by 100 (Total number of card bought previously) to get my answer. Hopefully that helps :)

7 0
2 years ago
What is the first step in solving the equation?<br> +4= -2
adell [148]

Answer:

adding +2 on both sides to remove the -2 then it would be 2=0

Step-by-step explanation:

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2 years ago
Nancy's garden has the dimensions shown 4 1/2 yard<br><br> 3 3/4 yd . She need find the area
Marina86 [1]

Answer:

The area of Nancy's garden is 16\frac{7}{8}\ yd^{2}

Step-by-step explanation:

I assume that the Nancy's garden is a rectangle shape

To find the area first convert mixed number to an improper fraction

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3\frac{3}{4}\ yd=\frac{3*4+3}{4}=\frac{15}{4}\ yd

Therefore

The area is equal to

A=\frac{9}{2}*\frac{15}{4}=\frac{135}{8}\ yd^{2}

convert to mixed number

\frac{135}{8}\ yd^{2=\frac{128}{8}+\frac{7}{8}=16\frac{7}{8}\ yd^{2}

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