Help me what if this answer

A certain electronics manufacturer found that the average cost C to produce x DVD/Blu- ray players can be found using the equati

NemiM [27]

Answer:

The minimum average cost is $643.75

It should be built 62.5 machines to achieve the minimum average cost

Step-by-step explanation:

The equation that represents the cost C to produce x DVD/BLU-ray players is C = 0.04x² - 5x + 800

To find the minimum cost differentiate C to equate it by 0 to find the average cost per machine and to find the value of the minimum cost

∵ C = 0.04x² - 5x + 800

- Differentiate C with respect to x

∴ $\frac{dC}{dx}=0.04(2)x^{2-1}-5(1)x^{1-1}+0$

∴ $\frac{dC}{dx}=0.08x-5$

- Equate $\frac{dC}{dx}$ by 0

∴ 0.08x - 5 = 0

- Add 5 to both sides

∴ 0.08x = 5

- Divide both sides by 0.08

∴ x = 62.5

That means the minimum average cost is at x = 62.5

Substitute the value of x in C to find the minimum average cost

∵ C = 0.04(62.5)² - 5(62.5) + 800

∴ C = 643.75

∵ C is the average cost

∴ The minimum average cost is $643.75

∵ x is the number of the machines

∴ It should be built 62.5 machines to achieve the minimum

average cost

4 0

3 years ago

Pleaseee helpp me i got one down!!!<br> (zoom in to see more clear)

iris [78.8K]

These 4 options are correct.

5 0

2 years ago

So me 3 ways you get to 100

In-s [12.5K]

10 x 10 = 100
20 + 20 + 20 + 20 +20 = 100
4 x 25 = 100

5 0

3 years ago

According to an article, 47% of adults have experienced a breakup at least once during the last 10 years. Of 9 randomly select

In-s [12.5K]

Answer:

a) $P(X=5)=(9C5)(0.47)^5 (1-0.47)^{9-5}=0.228$

b) $P(X=0)=(9C0)(0.47)^0 (1-0.47)^{9-0}=0.0033$

And replacing we got:

$P(X \geq 1)= 1-P(X$

c) $P(X=4)=(9C4)(0.47)^4 (1-0.47)^{9-4}=0.257$

$P(X=5)=(9C5)(0.47)^5 (1-0.47)^{9-5}=0.228$

$P(X=6)=(9C6)(0.47)^6 (1-0.47)^{9-6}=0.135$

And adding we got:

$P(4 \leq X \leq 6)= 0.257+0.228+0.135=0.620$

Step-by-step explanation:

Previous concepts

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".

Solution to the problem

Let X the random variable of interest, on this case we now that:

$X \sim Binom(n=9, p=0.47)$