Answer:
0.6%?
Step-by-step explanation:
Answer:
Step-by-step explanation:
Sampling Variability
Hope that helped! :)
Answer:
A
Step-by-step explanation:
You take the 64 teams, split it in half, and then the exponent is r
Answer:
<em>Rate of Pratap in still water is 4.5 miles/hour and rate of current is 0.5 miles/hour.</em>
Step-by-step explanation:
Pratap Puri rowed 10 miles down a river in 2 hours, but the return trip took him 2.5 hours.
We know that, ![Speed = \frac{Distance}{Time}](https://tex.z-dn.net/?f=Speed%20%3D%20%5Cfrac%7BDistance%7D%7BTime%7D)
So, the <u>speed of Pratap with the current</u> will be:
miles/hour
and the <u>speed of Pratap against the current</u> will be:
miles/hour.
Suppose, the rate of Pratap in still water is
and the rate of current is
.
So, the equations will be........
![x+y= 5 .............................. (1)\\ \\ x-y=4 .............................. (2)](https://tex.z-dn.net/?f=x%2By%3D%205%20..............................%20%281%29%5C%5C%20%5C%5C%20x-y%3D4%20..............................%20%282%29)
Adding equation (1) and (2) , we will get......
![2x=9\\ \\ x=\frac{9}{2}= 4.5](https://tex.z-dn.net/?f=2x%3D9%5C%5C%20%5C%5C%20x%3D%5Cfrac%7B9%7D%7B2%7D%3D%204.5)
Now, plugging this
into equation (1), we will get.....
![4.5+y=5\\ \\ y=5-4.5 =0.5](https://tex.z-dn.net/?f=4.5%2By%3D5%5C%5C%20%5C%5C%20y%3D5-4.5%20%3D0.5)
Thus, Pratap can row at 4.5 miles per hour in still water and the rate of the current is 0.5 miles/hour.
Step 1: multiple the second equation by 2 so that you get -1/4 for the coefficient of y, the same as in equation 1
equation 2 multiply by 2: 1/4 x - 1/4 y=38 ..........name this equation 3
subtract equation 1 from equation 3: (1/4 x -1/2 x)=38-10
-1/4 x = 28
x=-112
plug in x=-112 in any of the equation, you will get y=-264
so the answer is A