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Jet001 [13]
3 years ago
9

Find the GCF of 100x2y5 and 40x3y2 Include the factors please

Mathematics
1 answer:
Kamila [148]3 years ago
8 0

Answer:

20x^2y^2

Step-by-step explanation:

Found the prime factors of each term in order to find the greatest common factor (GCF)

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Please help me please help help me help please
notsponge [240]

Answer:

An equation of a line is written in the form y=mx+b. ”m” is the slope and ”b” is the y-intercept. So, substituting the values, the equation is y=-4x+1.

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7 0
3 years ago
Need help solving this problem ​
natka813 [3]

Answer:

Part 1: \frac{11-x}{5} or \frac{11}{5}-\frac{x}{5}

Part 2: \frac{9}{5}

Step-by-step explanation:

To start things off, you must put everything on the opposite side of y so that you only have the y variable left.

In this case, put x onto the other side, making it negative since it's flipped, so you get 5y=11-x (since the x is negative you're using subtraction from 11).

Next, divide both sides by 5 to make 5y into y:

\frac{5y}{5} =\frac{11}{5}-\frac{x}{5}

y=\frac{11}{5}-\frac{x}{5}

Then in this case you turn y=f(x), but the system did it for you, so all you have to put is \frac{11}{5}-\frac{x}{5}.

For the second part you must replace x with 2 since you need to find f(2).

\frac{11-2}{5}

Your answer for part 2 is \frac{9}{5}.

3 0
2 years ago
Enter the correct answer in the box. solve the equation x2 − 16x 54 = 0 by completing the square. fill in the values of a and b
poizon [28]

The roots of the given polynomials exist  $x=8+\sqrt{10}$, and $x=8-\sqrt{10}$.

<h3>What is the formula of the quadratic equation?</h3>

For a quadratic equation of the form $a x^{2}+b x+c=0$ the solutions are

$x_{1,2}=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}$

Therefore by using the formula we have

$x^{2}-16 x+54=0$$

Let, a = 1, b = -16 and c = 54

Substitute the values in the above equation, and we get

$x_{1,2}=\frac{-(-16) \pm \sqrt{(-16)^{2}-4 \cdot 1 \cdot 54}}{2 \cdot 1}$$

simplifying the equation, we get

$&x_{1,2}=\frac{-(-16) \pm 2 \sqrt{10}}{2 \cdot 1} \\

$&x_{1}=\frac{-(-16)+2 \sqrt{10}}{2 \cdot 1}, x_{2}=\frac{-(-16)-2 \sqrt{10}}{2 \cdot 1} \\

$&x=8+\sqrt{10}, x=8-\sqrt{10}

Therefore, the roots of the given polynomials are $x=8+\sqrt{10}$, and

$x=8-\sqrt{10}$.

To learn more about quadratic equations refer to:

brainly.com/question/1214333

#SPJ4

3 0
1 year ago
Read 2 more answers
Can someone please explain 7 and 8 to me? I really don’t get it that well. On 7, why are they congruent? Why is it false for 8?
Crazy boy [7]

Answer: Look below :)

Step-by-step explanation:

7. <u>AD</u> and <u>CD</u> are congruent.  Each of the triangles are the same in length and shape (both are right triangles). They are the same but are mirrored over the line <u>BD.</u>

8.  I have no idea. Sorry.

5 0
3 years ago
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Approximate square root of 83 to to the nearest integer.
frez [133]

Answer:

9.1

Step-by-step explanation:

3 0
3 years ago
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