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AnnZ [28]
3 years ago
15

Help please please please please ​

Mathematics
2 answers:
HACTEHA [7]3 years ago
5 0

Answer:

sorry it's blurry I can't fix it

Eva8 [605]3 years ago
3 0
Can you give more information such as a question ?
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I need help with this problem please
GrogVix [38]

Answer:

j = 2/3

Step-by-step explanation:

-1/3 = -1/2 j

Multiply each side by -2

-1/3 * -2 = -1/2 j * -2

2/3 =j

3 0
2 years ago
Read 2 more answers
*HELP PLEASE* <br> Will get BRAINLIEST answer!!!!
photoshop1234 [79]

When solving these proportions we just remember when moving a number from one side to the other if it started in the numerator it ends up in the denominator and vice versa.


I'll do it in two steps here for teaching purposes; it's not too hard to go directly to the answer.


\dfrac{13}{7} = \dfrac{10}{v}


13 v = 7(10)


v= \dfrac{7 \cdot 10 }{13} = \dfrac{70}{13} \approx 5.4

5 0
3 years ago
Read 2 more answers
10% of what number is 14?
alexdok [17]
140
10% is equal to 0.1

0.1 * 140 = 14

So the answer should be 140 as 10 percent of 140 is 14. 
6 0
3 years ago
Read 2 more answers
A number is 4 Hundreds more than 142. What is the number ?
weqwewe [10]
542 beacuse 142+400
4+1=5 4+0=a 2+0=2
4 0
3 years ago
Read 2 more answers
Someone help with this
elena-14-01-66 [18.8K]

The quadrants are I, II, III, and IV, (meaning 1, 2, 3, and 4). The first quadrant is in the upper right, which has both positive x and positive y values. The second quadrant is the upper left, which has negative x and positive y values. The third quadrant is the lower left, which has both negative x and y values. The fourth quadrant is the lower right, which has positive x and negative y values. Using this knowledge and our positive and negative signs, the following are the answers to questions 1-6.

1) (-4, -2) - Quadrant III, both x and y are negative

2) (0, -7) - This point is actually on the y-axis. The x value is 0 and the y value is -7, so the graph is 7 units down from the origin on the y-axis.

3) (0,0) - This point is the origin, or where the x and y axes cross (the middle of the graph).

4) (6, -9) - This point is in Quadrant IV, because it has a positive x value and a negative y value

5) (3,5) - This point is in Quadrant I, because both the x and y values are positive.

6) (8,0) - This point is on the x-axis. The y-value is zero, so this point is 8 units to the right of the origin between Quadrant I and Quadrant IV.

Using the knowledge presented above, to graph the points given to you in the second part of the problem, first you can figure out what quadrant or part of the graph the point is on. Then, you can count the number of units (squares on the graph) in the right direction (remember that up is positive on the y-axis and down is negative, and to the right is positive on the x-axis and to the left is negative) in order to plot the points. Then, you must connect the points that correspond to the same figure in order to create the figures.

Please comment if you have any questions!

Hope this helps!

7 0
3 years ago
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