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3 years ago

If you help me on all of these I'll mark you as a brainless

Mathematics

2 answers:

Tpy6a [65]3 years ago

4 0

9. 2,000
10. 3,200
11. 3,000
12. 1,800
13. 120
14. 125
15. 75
16. 30
17.
18.
I can't see the last two

sammy [17]3 years ago

3 0

Sure!
9)2,000
10) 3,200
11)3,000
12)2,000
13)120
14)125
15)80
16)35
And I can't see all the answers for 17 and 18

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In 2015, there were approximately 31,800 firearms fatalities. Express this quantity in deaths per hour

viva [34]

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3 years ago

If 12 men are needed to run 4 machines how many men are needed to run 20 machines

OLEGan [10]

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3 years ago

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Income amelia has a job babysitting for a neighbor. She is paid $20 plus $2.50 for each hour on the job. If amelia wants to earn

yarga [219]

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3 years ago

RectangleABCD has vertices at A(– 3, 1),B(– 2, – 1),C(2, 1), andD(1, 3). What is the area, in square units, of this rectangle? A

Anna [14]

Answer:

Option A. $10\ units^{2}$

Step-by-step explanation:

we know that

The area of the rectangle is equal to

A=LW

where

L is the length of rectangle

W is the width of rectangle

we have

$A(-3,1),B(-2,-1),C(2,1),D(1,3)$

Plot the vertices

see the attached figure

L=AD=BC

W=AB=DC

the formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

<em>Find the distance AD</em>

$A(-3,1),D(1,3)$

substitute in the formula

$AD=\sqrt{(3-1)^{2}+(1+3)^{2}}$

$AD=\sqrt{(2)^{2}+(4)^{2}}$

$AD=\sqrt{20}$

$AD=2\sqrt{5}\ units$

<em>Find the distance AB</em>

$A(-3,1),B(-2,-1)$

substitute in the formula

$AB=\sqrt{(-1-1)^{2}+(-2+3)^{2}}$

$AB=\sqrt{(-2)^{2}+(1)^{2}}$

$AB=\sqrt{5}$

$AB=\sqrt{5}\ units$

Find the area

$A=(2\sqrt{5})*(\sqrt{5})=10\ units^{2}$

4 0

3 years ago

How much would $200 invested at 5% interest compounded monthly be worth after 9years? Round your answer to the nearest cent

Feliz [49]

Answer:

$311.20

Step-by-step explanation:

Here we are required to use the Compound interest formula for finding the Amount at the end of 9th year

The formula is given as

$A=P(1+\frac{r}{n})^{tn}$

Where ,

A is the final amount

P is the initial amount = $200

r is the rate of interest = 5% annual = 0.05

n is the frequency of compounding in a year ( Here it is compounding monthly) = 12

t is the time period = 9

Now we substitute all these values in the formula and solve for A

$A=200(1+\frac{0.05}{12})^{9\times 12}$

$A=200(1+0.00416)^{108}$

$A=200(1.00416)^{108}$

$A=200 \times 1.556$

$A=311.20$

Hence the amount after 9 years will be $311.20

4 0

3 years ago