All categories

3 years ago

Help me please!?!?!?!

Mathematics

1 answer:

eduard3 years ago

6 0

The answer would be A

You might be interested in

Can you figure thus out?

babymother [125]

Answer:

315

Step-by-step explanation:

The number is divisible by 3,5,7 and 9. Since 3 is a factor of 9, this number is divisible by 5,7, and 9.

5x7x9= 315.

3 0

1 year ago

What is the whole nunnery 13,260,000in expanded form?

Katyanochek1 [597]

Answer:

13,000,000+200,000+60,000

Step-by-step explanation:

7 0

2 years ago

340 over 8 as a unit rate

Anastasy [175]

340/8 = 42.50 per unit

4 0

2 years ago

Read 2 more answers

15 points for someone who can answer & explain this to me thanks

iris [78.8K]

Answer:

see explanation

Step-by-step explanation:

Given

$\frac{9}{a^2+9a+20}$ , $\frac{7a}{a^2+11a+28}$

Factor the denominators of both fractions

$\frac{9}{(a+4)(a+5)}$ , $\frac{7a}{(a+4)(a+7)}$

The lowest common denominator of both fractions is (a + 4)(a + 5)(a + 7)

Multiply numerator/denominator of first fraction by (a + 7)

Multiply numerator/denominator of second fraction by (a + 5 )

$\frac{9(a+7)}{(a+4)(a+5)(a+7)}$ , $\frac{7a(a+5)}{(a+4)(a+5)(a+7)}$ , then

$\frac{9a+63}{(a+4)(a+5)(a+7)}$ , $\frac{7a^2+35a}{(a+4)(a+5)(a+7)}$

8 0

2 years ago

Javier's fuel tank holds 12 3/4 gallons of gasoline when completely full. He had some gas in the tank and added 10.3 gallons of

GenaCL600 [577]

Answer:

2.45 gallons of gasoline were in the tank before.

Step-by-step explanation:

Consider the provided information.

The tank can hold $12\frac{3}{4}$ gallons of gasoline when completely full. He had some gas in the tank and added 10.3 gallons of gasoline to fill it completely.

We need to find: How many gallons of gasoline were in the tank before Javier added some?

For this, we need to subtract added gallons of gasoline from the capacity of the tank.

$12\frac{3}{4}-10.3=\frac{51}{4}-10.3$

$=12.75-10.3$

$=2.45$

Hence, 2.45 gallons of gasoline were in the tank before.

6 0

2 years ago