1. 1 2/5 is 7/5 so he can cut 7
2. Is 8 times three that equals 24 and 24 plus 3 is 27 so 27/8
I did this in first grade so easy but.. whatever, okay so first you would need to add 36, 28, and 24 which is 88. Then 88 divided by 11= 8 pieces of fruit per bag.
Answer:
Step-by-step explanation:
What is the question?
Answer:
Ben's error is that he thought both pizzas were the same size, well what was left and in the beginning.
Step-by-step explanation:
Even if both 1/4 is left, that doesn't mean you started with the same amount. Also, both 1/4 pieces are different shapes and sizes, making him wrong.
Hope this helped!! :)
Answer:
At a certain pizza parlor,36 % of the customers order a pizza containing onions,35 % of the customers order a pizza containing sausage, and 66% order a pizza containing onions or sausage (or both). Find the probability that a customer chosen at random will order a pizza containing both onions and sausage.
Step-by-step explanation:
Hello!
You have the following possible pizza orders:
Onion ⇒ P(on)= 0.36
Sausage ⇒ P(sa)= 0.35
Onions and Sausages ⇒ P(on∪sa)= 0.66
The events "onion" and "sausage" are not mutually exclusive, since you can order a pizza with both toppings.
If two events are not mutually exclusive, you know that:
P(A∪B)= P(A)+P(B)-P(A∩B)
Using the given information you can use that property to calculate the probability of a customer ordering a pizza with onions and sausage:
P(on∪sa)= P(on)+P(sa)-P(on∩sa)
P(on∪sa)+P(on∩sa)= P(on)+P(sa)
P(on∩sa)= P(on)+P(sa)-P(on∪sa)
P(on∩sa)= 0.36+0.35-0.66= 0.05
I hope it helps!