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vovikov84 [41]
3 years ago
11

Hey can someone please help explain and answer this 1 question. There's a picture. Thank you!

Mathematics
1 answer:
zmey [24]3 years ago
3 0
//You can substitute some values in to find out, for example (1, -5) and (5, -5) are good.
Using this method, you can deduce that it would be A
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All diameters of a circle have the same blank
TEA [102]

Answer:

the width and diameter are the same because all such pairs of parallel tangent lines have the same distance.

Step-by-step explanation:

In geometry, a diameter of a circle is any straight line segment that passes through the center of the circle and whose endpoints lie on the circle. ... For a curve of constant width such as the Reuleaux triangle, the width and diameter are the same because all such pairs of parallel tangent lines have the same distance.

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3 years ago
Mason stands on the 5th step of a vertical ladder. The ladder has 15 steps, and the height difference between consecutive steps
MrMuchimi
Which number type?  I'd go with Whole numbers or integers, since the steps are just whole values one step after the next.

well, an appropriate domain, namely the inputs, well, He's on the 5th step, there are 15 steps, so he's really 10 steps away from the top of the ladder, and going down N being negative, he's -5 steps from the ground.

{ N | N ∈ ℤ ,  -5 ⩽ N ⩽ 10 }
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3 years ago
Read 2 more answers
Which equation correctly shows the absoulte vaule of -8
olga2289 [7]

Answer:

|-8|=8

Step-by-step explanation:

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3 years ago
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Expressions in 1 variable if x=15. -5x-71
Shkiper50 [21]

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-146

Step-by-step explanation:

3 0
4 years ago
9. Plot the points A (-2,3), B(2,-3), C(2,3) ,D(-2,3) join the points and find the distance between each point.
pav-90 [236]

Answer:

AB=7.21 unit

BC=6 unit

CD=7.21 unit

AD= 6 unit

AC=4 unit

BD=4 unit

Step-by-step explanation:

Coordinates of A =(-2,3)

Coordinates of B = (2,-3)

Coordinates of C = (2,3)

Coordinates of D =(-2,-3)

Distance formula :d = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

A=(x_1,y_1)=(-2,3)\\B=(x_2,y_2)=(2,-3)\\AB = \sqrt{(2+2)^2+(-3-3)^2}

AB=7.21 unit

B=(x_1,y_1)=(2,-3)\\C=(x_2,y_2)=(2,3)\\BC=\sqrt{(2-2)^2+(3+3)^2}

BC=6

C=(x_1,y_1)=(2,3)\\D=(x_2,y_2)=(-2,-3)\\CD=\sqrt{(-2-2)^2+(-3-3)^2}

CD=7.21

A=(x_1,y_1)=(-2,3)\\D=(x_2,y_2)=(-2,-3)\\AD=\sqrt{(-2+2)^2+(-3-3)^2}

AD=6

A=(x_1,y_1)=(-2,3)\\C=(x_2,y_2)=(2,3)

AC=\sqrt{(2+2)^2+(3-3)^2}

AC=4

B=(x_1,y_1)=(2,-3)\\D=(x_2,y_2)=(-2,-3)

BD=\sqrt{(-2-2)^2+(-3+3)^2}

BD=4

4 0
3 years ago
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