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sattari [20]
3 years ago
14

There is a quadrilateral MNPQ in which side MN is congruent to side PQ and side NP is parallel to side MQ. The diagonal MP and t

he diagonal NQ intersect each other at point R. If MP = 6x − 5, QR = 3x + 1, and RN = 6, what is QN?
Mathematics
1 answer:
8_murik_8 [283]3 years ago
5 0

Answer: QN = 12

Step-by-step explanation: This quadrilateral is a paralelogram because its 2 opposite sides (NP and MQ) are parallel and the other 2 (MN and PQ) are congruent.

In paralelogram, diagonals bisect each other, which means QR = RN.

If QR = RN:

QR = 6

Then,

QN = QR + RN

QN = 6 + 6

QN = 12

<u>The diagonal QN of quadrilateral MNPQ is </u><u>QN = 12</u><u>.</u>

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Katyanochek1 [597]

Answer:

x = 100 is equivalent to z = -1.75

Step-by-step explanation:

7 0
3 years ago
Please help me with the below question.
tresset_1 [31]

We have the following three conclusions about the <em>piecewise</em> function evaluated at x = 14.75:

  1. \lim_{t \to 14.75^{-}} f(t) = 66.
  2. \lim_{t \to 14.75^{+}} f(t) = 10.
  3. \lim_{t \to 14.75} f(t) does not exist as \lim_{t \to 14.75^{-}} f(t) \ne  \lim_{t \to 14.75^{+}} f(t).

<h3>How to determinate the limit in a piecewise function</h3>

In a <em>piecewise</em> function, the limit for a given value exists when the two <em>lateral</em> limits are the same and, thus, continuity is guaranteed. Otherwise, the limit does not exist.  

According to the definition of <em>lateral</em> limit and by observing carefully the figure, we have the following conclusions:

  1. \lim_{t \to 14.75^{-}} f(t) = 66.
  2. \lim_{t \to 14.75^{+}} f(t) = 10.
  3. \lim_{t \to 14.75} f(t) does not exist as \lim_{t \to 14.75^{-}} f(t) \ne  \lim_{t \to 14.75^{+}} f(t).

To learn more on piecewise function: brainly.com/question/12561612

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2 years ago
Pleasee helppppp im so close to being done and this is my last day !!
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ANSWER FOR UR QUESTION!

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7 0
2 years ago
Lisa is seven times as old as her brother. She will be four times as old as her brother in three years. Represent the above situ
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Answer:

3

Step-by-step explanation:

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2 years ago
The quantity r varies jointly with t and u and inversely with s when t= -12, u= -7, and s= -4, r= -126. Find r when t= -8, u= 8,
vichka [17]

Answer:

r = 64

Step-by-step explanation:

r = (k*t*u)/s

Where,

k = constant of proportionality

t = -12,

u= -7,

s= -4,

r= -126.

r = (k*t*u)/s

-126 = (k*-12*-7)/-4

-126 * -4 = 84k

504 = 84k

k = 504/84

k = 6

Find r when t= -8, u= 8, and s= -6.

r = (k*t*u)/s

= (6*-8*8) / -6

= -384 / -6

= 64

r = 64

6 0
3 years ago
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