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3 years ago

Select the TRUE statement.

2 answers:

8 0

Hi. y=2 A) 9(2)- 2(2) ≠11(2) 18-4≠22 B) 9(2)-2(2)= 18(2) 18-4≠36 C) 9(2) - 2(2) = 0 18 - 4 ≠ 0 D) 9(2)-2(2)= 7(2) 18-4=14; 14=14. The answer is : "D".

Salsk061 [2.6K]3 years ago

7 0

D. all you do is just subtract 9-2. that obviously equals 7....

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A trough of water is 20 meters in length and its ends are in the shape of an isosceles triangle whose width is 7 meters and heig

Vaselesa [24]

Answer:

a) Depth changing rate of change is $0.24m/min$ , When the water is 6 meters deep

b) The width of the top of the water is changing at a rate of $0.17m/min$ , When the water is 6 meters deep

Step-by-step explanation:

As we can see in the attachment part II, there are similar triangles, so we have the following relation between them $\frac{3.5}{10} =\frac{a}{h}$ , then $a=0.35h$ .

a) As we have that volume is $V=\frac{1}{2} 2ahL=ahL$ , then $V=(0.35h^{2})L$ , so we can derivate it $\frac{dV}{dt}=2(0.35h)L\frac{dh}{dt}$ due to the chain rule, then we clean this expression for $\frac{dh}{dt}=\frac{1}{0.7hL}\frac{dV}{dt}$ and compute with the knowns $\frac{dh}{dt}=\frac{1}{0.7(6m)(20m)}2m^{3}/min=0.24m/min$ , is the depth changing rate of change when the water is 6 meters deep.

b) As the width of the top is $2a=0.7h$ , we can derivate it and obtain $\frac{da}{dt}=0.7\frac{dh}{dt} =0.7*0.24m/min=0.17m/min$ The width of the top of the water is changing, When the water is 6 meters deep at this rate

8 0

3 years ago

Solve for X: 5(2x-12)=140

Mrac [35]

Answer:

x=20

Step-by-step explanation:

10x-60=140

10x=140+60

10x=200

x=20

6 0

3 years ago

Read 2 more answers

Suppose an=3an-1 -5an-2 -4an-3. and a4= -7, a5=-36, a6=-85 , find a1 , a2, a3

maria [59]

Answer:

$a_1=4\\\\a_2=0\\\\a_3=3$

Explanation:

The equation is:

$a_n=3a_{n-1}-5a_{n-2}-4a_{n-3}$

and

$a_4=-7, a_5=-36, a_6=-85$

1. Subsittute n = 6 into the equation:

$a_6=3a_{5}-5a_{4}-4a_{3}$

Now subsititute the known values:

$-85=3(-36)-5(-7)-4a_{3}$

You can solve for $a_3$

$-85=-108+35-4a_{3}\\\\4a_3=12\\\\a_3=12/4\\\\a_3=3$

2. Substitute n = 5 into the equation:

$a_5=3a_{4}-5a_{3}-4a_{2}$

Substitute the known values and solve for $a_2$

$-36=3(-7)-5(3)-4a_{2}\\\\4a_2=-21-15+36=0\\\\a_2=0$

3. Substitute n = 4 into the equation, subsitute the known values and solve for $a_1$

$a_4=3a_{3}-5a_{2}-4a_{1}$

$-7=3(3)-5(0)-4a_{1}\\\\4a_1=9+7=16\\\\a_1=4$

7 0

3 years ago

A farmer is putting apples and oranges into boxes to sell at a market. He has 64 apples and 24 oranges . What is the greatest nu

dexar [7]

Well you could do 8 apple and 3 oranges per box since there are 64 apples and 24 oranges. You can either use trial and error to see what what values give you an answer of 8 for each amount of fruit. Or you can find the greatest common factor which happens to be 8 in this case, and divide each by that can come to the conclusion that 8 apples go into 8 boxes and 3 oranges do into 8 boxes Over all the answer would be 8 apples and oranges per each box, to have a total number of 8 boxes.

I hope this helps!

5 0

3 years ago

a picture contains 2/3 quart of water if an equal amount of water is poured into each of six glasses how much water will each gl

Ulleksa [173]

Each glass will contain 1/6 quart of water

7 0

3 years ago