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eimsori [14]
3 years ago
11

Answer fast please and can you show work

Mathematics
1 answer:
alexdok [17]3 years ago
5 0

Answer:

a)

b) SSA does not constitute a proof. You need another fact.

Step-by-step explanation:

You should actually show congruency first

Angles opposite = sides are themselves equal.

<C = 50o

<J = 50o

But there is nothing that says x is 1/2 of <JAC

So it's unsolvable

Part B also has the same conclusion.

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PLEASE I NEED HELP
klemol [59]

Answer: 0.25 feet


Step-by-step explanation:

Given: Jonathon has paper strips that are all equal in length.

Let x be the length of each paper strip.

Since John lines them up end to end, the length of the line of paper strips= 3 feet

Also total strips used= 12

Therefore, length of line of strips=12x=3\ feet

\\\Rightarrow\ x=\frac{1}{4}\ feet\\\Rightarrow\ x= 0.25\ feet

hence, if Jonathan is correct then the length of each strip will be 0.25 feet.


8 0
3 years ago
Quadratic Functions Helppp please!!! questions attached below
OleMash [197]

Answer:

Q 30) x = -3 or x = 12.

Q 31) x = 1 or x = 2.

Q 32) x = -1/2 or x = 8.

Q 33) x = 2/5 or x = 3.

Q 34) x = 1.80424764151 or x = -0.5542476415.

Q 35) x = 1.5 or x = -1/3.

Step-by-step explanation:

Q 30)

x^2 - 9x - 36 = 0.

Solving by factoring:

Multiplying 1 and 36 yields 36. The factors whose difference results in 9 are 12 and 3. Therefore:

x^2 - 12x + 3x - 36 = 0.

x(x - 12) + 3(x - 12) = 0.

(x + 3)(x - 12) = 0.

Either x + 3 = 0 or x - 12 = 0.

Therefore, x = -3 or x = 12.

Q 31)

x^2 - 3x + 2 = 0.

Solving by factoring:

Multiplying 1 and 2 yields 2. The factors whose sum results in 3 are 2 and 1. Therefore:

x^2 - 2x - x + 2 = 0.

x(x - 2) - 1(x - 2) = 0.

(x - 1)(x - 2) = 0.

Either x - 1 = 0 or x - 2 = 0.

Therefore, x = 1 or x = 2.

Q 32)

2x^2 - 15x - 8 = 0.

Solving by factoring:

Multiplying 2 and 8 yields 16. The factors whose difference results in 15 are 16 and 1. Therefore:

2x^2 - 16x + x - 8 = 0.

2x(x - 8) + 1(x - 8) = 0.

(2x + 1)(x - 8) = 0.

Either 2x + 1 = 0 or x - 8 = 0.

Therefore, x = -1/2 or x = 8.

Q 33)

5x^2 - 17x + 6 = 0.

Solving by factoring:

Multiplying 5 and 6 yields 30. The factors whose sum results in 17 are 15 and 2. Therefore:

5x^2 - 15x - 2x + 6 = 0.

5x(x - 3) - 2(x - 3) = 0.

(5x - 2)(x - 3) = 0.

Either 5x - 2 = 0 or x - 3 = 0.

Therefore, x = 2/5 or x = 3.

Q 34)

4x^2 - 5x - 4 = 0.

Solving by completing the square:

4x^2 - 5x = 4.

x^2 - 5x/4 = 1.

(x)^2 - 2*(x)*(5/8) + (5/8)^2 = 1 + (5/8)^2.

(x - 5/8)^2 = 1 + 25/64.

(x - 5/8)^2 = 89/64.

x - 5/8 = ±1.17924764151.

x - 5/8 = 1.17924764151 or x - 5/8 = -1.17924764151.

Therefore, x = 1.80424764151 or x = -0.5542476415.

Q 35)

6x^2 - 7x - 3 = 0.

Solving by quadratic formula:

x = (-b ± √(b^2 - 4ac))/2a.

a = 6, b = -7, and c = -3.

x = (-(-7) ± √((-7)^2 - 4*(6)*(-3)))/2(6).

x = (7 ± √(49 + 72))/12.

x = (7 ± √(121))/12.

x = (7 ± 11)/12.

x = (7 + 11)/12 or x = (7 - 11)/12.

x = 18/12 or x = -4/12.

Therefore, x = 1.5 or x = -1/3.

In summary:

Q 30) x = -3 or x = 12!!!

Q 31) x = 1 or x = 2!!!

Q 32) x = -1/2 or x = 8!!!

Q 33) x = 2/5 or x = 3!!!

Q 34) x = 1.80424764151 or x = -0.5542476415!!!

Q 35) x = 1.5 or x = -1/3!!!

5 0
4 years ago
Factorise 18u²-50y completely.​
Rufina [12.5K]

Answer:

2(3u  + 5 \sqrt{y} )(3u - 5 \sqrt{y} )

Step-by-step explanation:

18 {u}^{2}  - 50y \\  \\  = 2[9 {u}^{2}  - 25y]  \\  \\  = 2[(3 {u})^{2}  - (5 \sqrt{y} )^{2} ]   \\  \\  = 2(3u  + 5 \sqrt{y} )(3u - 5 \sqrt{y} )

6 0
3 years ago
Can some one help me with 1,3,and 5
FrozenT [24]

1. 2/100 or 1/50, as 0.02 is equal to 2 hundreths. Simplifying gets you 1/50

3. 1/2 or 50/100, as 0.50 is equal to 0.5 which is equal to 50 hundreths. Simplify to get 1/2

5. 88/100 or 44/50 , as 0.88 is equal to 88 hundreths. After simplifying, you get 44/50

Depending on your teacher, you may be told to not simplify. It depends

8 0
3 years ago
I NEED HELP PLEASE!!!
Anvisha [2.4K]

Answer: Part a) translate g(x) 6 units to the right, Translate f(x) 6 units to the left

Part b) k=3 (slope)

Step-by-step explanation:

7 0
3 years ago
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