Answer:
its easy
Explanation:
there are are 5 main rules
in binary there are 2 number 0 and 1
0 + 0 = 0
0 + 1 = 1
1+0=1
1+1=0 carry 1
e . g
1 1 1
1 0 1 0 1 0
+ 1 1 0 0 1 0
-------------------------
1 1 1 1 1 0 0
*in bold are the ones that you need to carry.
in decimal there are 10 possible numbers 0- 9
when you do 1 + 9 it becomes 10, this can be done easily, however if you do 1 + 9 in a table like above, you will get 0 for the first column and you will carry 1 to the next column .
in binary is the same idea but using on 2 numbers 1 and 0
e.g
1
1
+ 9
----------
1 0
*in bold are the ones that you need to carry.
hope it helps and good luck in your exam.
Answer:
a. Telnet transmissions are not encrypted.
Explanation:
Indeed, since <em>Telnet transmissions are not encrypted,</em> all the information sent, and even the characters typed in the telnet console are sent in clear text.
This is a security issue, since any other device in the same network will receive a copy of the information (packets) sent. For default, all the devices, except for the server expecting to receive the information, will discard the packets. However it is easy to actively <em>listen </em>and keep those packets, wich will contain the information in plain text and human readable.
Answer:
There are usually three stages to writing a program: Coding. Compiling. Debugging.
Answer:
Following code will store the largest value in array parkingTickets in the variable mostTickets
mostTickets = parkingTickets[0];
for(int k = 0; k<parkingTickets.length; k++)
{
if(parkingTickets[i]>mostTickets)
{
mostTickets = parkingTickets[i];
}
}
Explanation:
In the above code segment, initially the number of tickets at first index is assumed as largest value of tickets in array.
Then using a for loop each value in the array parkingTickets is compared with the current mostTickets value.
If the compared value in parkingTickets array is larger than the current mostTickets value. Then that value is assigned to mostTickets.
This process is repeated for all elements in array.
Thus after looping through each element of array the largest value in array will get stored in mostTickets variable.
Make me brainlestttt please and thank you and the answer is no
