Answer:
See explaination
Explanation:
Here are the steps taken to draw the diagram!
opcode0 and the opcode1 signals are inverted/not to determine the case whether it is 00, 01, 10, 11.
Then they are 'and'ed with the corresponding Zero/lt signal to confirm if the case is true, for eg. zero = 1 if opcode = 00 (beq).
Then all the cases are 'or'ed to get the Branch signal!
See attachment for the diagram
Edits in the document are called, C. Track changes
Choosing the "Quick Print" button will print to the default print (Answer is B). The quick print function is accessible in the Quick Access Tool bar . By clicking the drop down arrow of the quick access tool bar it will let you choose different types of default access including your Quick print.
Answer:
kinda look it up!!!
Explanation:
go to code.org free coding
Answer:
The program to this question can be describes as follows:
Program:
#include <stdio.h> //defining header file
int main() //defining main method
{
int n,i,x=0; //defining integer variable
printf("Enter a number: "); //print message
scanf("%d",&n); //input value from the user
printf("%d\n",n); //print input value
for(i=1;i<n;i++) //loop to count reverse number
{
x=n-i; //calculate value
printf("%d\n",x); //print value
}
return 0;
}
Output:
Enter a number: 3
3
2
1
Explanation:
- In the above program, three integer variable "n,i and x" is declared, in which variable n we take input from the user end and the variable i and x is used in the loop to calculate the value in the reverse order.
- In the next step, a loop is declared, in which the variable x calculates the value in reverse order and uses a print method to print its value.
