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Mila [183]
3 years ago
5

Write a program that uses nested loop or for statements to display Pattern A below, followed by an empty line and then another s

et of loops that displays Pattern B. Once again no setw implementation is allowed here but you must use nested loop or for statements with proper indentation to generate these patterns. Use meaningful variable identifier names, good prompting messages and appropriate comments for each loop segment as well as other sections in the body of your program.
Note: Each triangle has exactly seven rows and the width of each row is an odd number. The triangles have appropriate labels displayed.


Pattern A

+

+++

+++++

+++++++

+++++++++

+++++++++++

+++++++++++++

Pattern B

+++++++++++++

+++++++++++

+++++++++

+++++++

+++++

+++

+
Computers and Technology
1 answer:
JulsSmile [24]3 years ago
8 0

Answer:

public class Pyramid {

   public static void main(String[] args) {

             int h = 7;

       System.out.println("Pattern A");

               for(int i = 1; i <= h; ++i)

               {

                   for(int j = 1; j <= i; ++j) {

                       System.out.print("+");

                   }

                   System.out.println();

               }

       System.out.println();

       System.out.println("Pattern B");

               for (int i = 1; i<=h; ++i)

               {

                 for(int j = h; j >=i; --j){

                     System.out.print("+");

                 }

                   System.out.println();

               }

           }

       }

Explanation:

  • The trick in this code is using a nested for loop
  • The outer for loop runs from i = 0 to the heigth of the triangle (in this case 7)
  • The inner for loop which prints the (+) sign runs from j = 0 to j<=i
  • It prints the + using the print() function and not println()
  • In the pattern B the loop is reversed to start from  i = height
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Answer:

In Python:

entry = input("Sentence: ")

while True:

   if entry.count(",") == 0:

       print("Error: No comma in string")

       entry = input("Sentence: ")

   elif entry.count(",") > 1:

       print("Error: Too many comma in input")

       entry = input("Sentence: ")

   else:

       ind = entry.index(',')+1

       if entry[ind].isnumeric() == False:

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       else:

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Explanation:

This prompts the user for a sentence

entry = input("Sentence: ")

The following loop is repeated until the user enters a valid entry

while True:

This is executed if the number of commas is 0

<em>    if entry.count(",") == 0:</em>

<em>        print("Error: No comma in string")</em>

<em>        entry = input("Sentence: ")</em>

This is executed if the number of commas is more than 1

<em>    elif entry.count(",") > 1:</em>

<em>        print("Error: Too many comma in input")</em>

<em>        entry = input("Sentence: ")</em>

This is executed if the number of commas is 1

   else:

This calculates the next index after the comma

       ind = entry.index(',')+1

This checks if the character after the comma is a number

       if entry[ind].isnumeric() == False:

If it is not a number, the print statement is executed

<em>            print("Comma not followed by an integer")</em>

<em>            entry = input("Sentence: ")</em>

If otherwise, the loop is exited

<em>        else:</em>

<em>            break</em>

This prints valid input, when the user enters a valid string

print("Valid Input")

Note that: entry = input("Sentence: ") <em>is used to get input</em>

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For example, if the AL contains binary 1000 1111, the SHR AL, 2 operation will cause the following to happen

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Notice;

(i) that there are two shifts - one at a time.

(ii) that the bits in bold face are the bits in the AL after the shift. Those that in regular face are those in the carry flag.

(iii) that the new bits added to the AL after a shift are the ones in bracket. They are always set to 0.

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