I'll give you a hint. <u><em>You had to used pemdas stands for: p-parenthesis, e-exponents, m-multiply, d-divide, a-add, and s-subtracting.</em></u>
First you had to calculate with parenthesis first.

Then you add and subtract from left to right.

Final answer 
Hope this helps!
And thank you for posting your question at here on brainly, and have a great day.
-Charlie
Answer:
2, 4
Step-by-step explanation:
Let there are two unknown consecutive pairs of even integers 2n and 2n+2.
If the sum of the reciprocals of those two integers is 3/4, then we can write,
1/2n +1/(2n+2) =3/4 ...... (1)
Solving this above equation we can check whether the integers exist or not.
Now, from equation (1) we get,
1/n +1/(n+1) =3/2
⇒
⇒4n +2 =3n²+3n
⇒3n²-n-2 =0
⇒ (n-1)(3n+2) =0
⇒ (n-1) =0 {Since if (3n+2) =0 then, n will be a negative fraction, which is not possible}
⇒ n=1
∴ 2n =2 and 2n+2 =4
Hence, the two integers are 2, 4. (Answer)
<span>7/10x-1/5=4 should be written as (7/10)x - 1/5 + 4
or as 7x/10 - 1/5 = 4.
Multiply all 3 terms of the latter equation by 10 to eliminate fractions:
7x - 2 = 40
Then 7x =42, and x = 6.</span>