Answer:
14.81%
Step-by-step explanation:
A fair six-sided dice has a total of six sides meaning that there are 6 possible outcomes for each dice roll. If two of the faces on the dice are red, then the possibility of rolling a red on a single dice roll would be 2/6, while the probability of rolling anything else would be 4/6 because there are 4 other sides left. Now if we roll three seperate dice, in order to calculate the probability of getting only one red face we need to multiply the probability of getting a red face on the first dice by the probability of the other two dice getting anything else.
2/6 * 4/6 * 4/6 = 32/216 or 0.1481
We can multiply this decimal by 100 to get the percentage value...
0.1481 * 100 = 14.81%
Answer:
d=1／2
Step-by-step explanation:
Pair up the terms into separate groups. Then factor each group individually (pull out the GCF). Once that is finished, you factor out the overall GCF to complete the full factorization.
8r^3 - 64r^2 + r - 8
(8r^3 - 64r^2) + (r - 8)
8r^2(r - 8) + (r - 8)
8r^2(r - 8) + 1(r - 8)
(8r^2 + 1)(r - 8)
So the final answer is (8r^2 + 1)(r - 8)
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Edit:
Problem 1b) Follow the same basic steps as in part A
28v^3 + 16v^2 - 21v - 12
(28v^3 + 16v^2) + (-21v - 12)
4v^2(7v + 4) + (-21v - 12)
4v^2(7v + 4) - 3(7v + 4)
(4v^2 - 3)(7v + 4)
The answer to part B is (4v^2 - 3)(7v + 4)
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Second Edit:
I apologize for the first edit. I misread what you were asking initially. Here is problem 2A. We follow the same basic steps as in 1a) and 1b). You'll need to rearrange terms first
27mz - 12nc + 9mc - 36nz
27mz + 9mc - 12nc - 36nz
(27mz + 9mc) + (-12nc - 36nz)
9m(3z + c) + (-12nc - 36nz)
9m(3z + c) -12n(c + 3z)
9m(3z + c) -12n(3z + c)
(9m - 12n)(3z + c)
3(3m - 4n)(3z + c)
Answer: If you are solving for x, then thee is no solution
Step-by-step explanation:
Answer: 48/25
Step-by-step explanation:
