Answer:
A) The model exists: f(x) = -3x^2 +4x -4
Step-by-step explanation:
A quadratic model will always exist for 3 given points, provided they are not on a line. In that case, a linear model is appropriate.
Here, the slope between -1 and 0 is positive, and the slope between 0 and 3 is negative. Thus, we know these points are not collinear, and a model must exist.
The model is most easily found using a quadratic regression tool. Such is shown in the attachment. It tells us that ...
f(x) = -3x^2 +4x -4
Answer:
Okay so I am not positive but I will try to help you out. Okay so the line of best fit would positive. Because it is all going up. The approximate slope is 3/4 Because slope is change in y over change in x. The y intercept of the line of best fit would be (0,0). This is because when drawing the line you can see that it would intercept the y-axis at zero. My steps taken were basically just looking at it and peicing everything together. If you want to get more involved with slope you could pick to coordinates which I will include and do change in y over change in x.
My points I will pick are (1,1) and (5,2)
2-1/5-1=3/4
therefore approximate slope is 3/4
Like I said I am not positive but I am just trying to help out in some way.
If something is incorrect please inform me. If this helps also please inform me.
64x2.40 = 153.6
64x1.90 = 121.6
add 153.6 to 121.6
275.2
