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Elena-2011 [213]
3 years ago
7

Helppppppppp

Mathematics
1 answer:
Anettt [7]3 years ago
7 0

Answer:

The total number of U.S. high school students that played on a sports team that year can be estimated to be 7,950,000.

Step-by-step explanation:

From the random sample, we can expect that \frac{250000}{500000}=\frac{1}{2} of all students played on a sports team that year. So in the bigger sample of 15900000 high school students, we can expect 15900000 \cdot \frac{1}{2} = 7950000 students to have played on a sports team that year.

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2/5 of the students in the class received an invitation to Sari's party. (a) if there are 35 students in Sari's class, how many
astraxan [27]

a) (2/5) x 35 = 14 students received invitations

b) 35-14 = 21 students didn’t receive invitations

3 0
3 years ago
HELP ASAP!!!!!!!!PLEASE<br><br> Solve for x. Please explain. Thank you
Stella [2.4K]

The values are x=8 and y=10

Explanation:

From the figure, we can see that the two quadrilaterals are similar.

Thus, by the property of quadrilateral, for similar quadrilaterals, their corresponding angles and sides are congruent. Thus, we have,

∠D = ∠S, ∠E = ∠P, ∠G = ∠R and ∠F = ∠Q

Also, GF = QR and DE = PS

Where QR = 2x-4 and ∠D = 102°, ∠G = 84° and ∠F = 68°, ∠Q = (6y+x)°

Hence, to determine the value of x for the side QR, we have,

Equating the values in GF = QR,we get,

12=2x-4\\16=2x\\8=x

Thus, the value of x is 8.

Substituting x in the angle Q to determine the value of y.

Thus, we have,

∠F = ∠Q

68=6y+x\\68=6y+8\\60=6y\\10=y

Thus, the value of y is 10.

Hence, The values are x=8 and y=10

8 0
3 years ago
A circular swimming pool has a diameter of 40 meters. The depth of the pool is constant along west-east lines and increases line
Nataliya [291]

Answer:

Volume is 2000\pi\ m^{3}

Solution:

As per the question:

Diameter, d = 40 m

Radius, r = 20 m

Now,

From north to south, we consider this vertical distance as 'y' and height, h varies linearly as a function of y:

iff

h(y) = cy + d

Then

when y = 1 m

h(- 20) = 1 m

1 = c.(- 20) + d = - 20c + d              (1)

when y = 9 m

h(20) = 9 m

9 = c.20 + d = 20c + d                  (2)

Adding eqn (1) and (2)

d = 5 m

Using d = 5 in eqn (2), we get:

c = \frac{1}{5}

Therefore,

h(y) = \frac{1}{5}y + 5

Now, the Volume of the pool is given by:

V = \int h(y)dA

where

A = r\theta

A = rdr\ d\theta

Thus

V = \int (\frac{1}{5}y + 5)dA

V = \int_{0}^{2\pi}\int_{0}^{20} (\frac{1}{5}rsin\theta + 5) rdr\ d\theta

V = \int_{0}^{2\pi}\int_{0}^{20} (\frac{1}{5}r^{2}sin\theta + 5r}) dr\ d\theta

V = \int_{0}^{2\pi} (\frac{1}{15}20^{3}sin\theta + 1000) d\theta

V = [- 533.33cos\theta + 1000\theta]_{0}^{2\pi}

V = 0 + 2\pi \times 1000 = 2000\pi\ m^{3}

7 0
3 years ago
Assume each figure shown has the same orientation. Which figure is the image of square LMNP after a translation of
umka21 [38]

Figure 4 is the image of the square LMNP after the translation.

<u>Step-by-step explanation:</u>

Let us see the coordinates of the pre image LMNP as,

L (-3,1)

M(-1,1)

N(-1,-1)

P(-3,-1)

after translation of (x,y) → (x+5, y -3) the coordinates of the image obtained as,

L'(2,-2)

M'(4,-2)

N'(4,-4)

P'(2,-4) which matches the image 4.

8 0
3 years ago
Read 2 more answers
Use the model to solve for x.
nadezda [96]
Your answer is C) x=8
4 0
3 years ago
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