All categories

3 years ago

Evaluate if m= -6 and n= -2 (2m divided by n) please help!!11!!

1 answer:

5 0

$\frac{2m}{n}$
you put in -6 for m and -2 for n
$\frac{2( - 6)}{ - 2}$
the 2/2 =1 but one is negative so it's -1
$- 1( - 6)$
negative times a negative is a positive
$6$

You might be interested in

a standard 52 card deck of cards is shuffled and then a 12-card hand is dealt from the deck. How many different outcomes are pos

kow [346]

The clout come would be 13

5 0

3 years ago

Write the following expression without negative exponents and without parentheses.

jeka94

Answer:

1/10x * 1/10x

Step-by-step explanation:

Writing a term with negative exponents is the same as putting it in a fraction.

10x^-1 = 1/10x

so the expression would be

1/10x * 1/10x

8 0

2 years ago

R 2x-6+3=6x-5 please help

frozen [14]

♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️

$2x - 6 + 3 = 6x - 5$

$2x - 3 = 6x - 5$

$6x - 5 = 2x - 3$

Add sides 5

$6x - 5 + 5 = 2x - 3 + 5$

$6x = 2x + 2$

Subtract sides 2x

$- 2x + 6x = - 2x + 2x + 2$

$4x = 2$

Divide sides by 4

$\frac{4x}{4} = \frac{2}{4} \\$

$x = \frac{1}{2} \\$

_________________________________

CHECK :

$2( \frac{1}{2} ) - 3 = 6( \frac{1}{2} ) - 5 \\$

$1 - 3 = 3 - 5$

$- 2 = - 2$

Thus the solution is correct....

♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️

3 0

2 years ago

Read 2 more answers

A tank with a capacity of 1000 L is full of a mixture of water and chlorine with a concentration of 0.02 g of chlorine per liter

faltersainse [42]

At the start, the tank contains

(0.02 g/L) * (1000 L) = 20 g

of chlorine. Let c (t ) denote the amount of chlorine (in grams) in the tank at time t .

Pure water is pumped into the tank, so no chlorine is flowing into it, but is flowing out at a rate of

(c (t )/(1000 + (10 - 25)t ) g/L) * (25 L/s) = 5c (t ) /(200 - 3t ) g/s

In case it's unclear why this is the case:

The amount of liquid in the tank at the start is 1000 L. If water is pumped in at a rate of 10 L/s, then after t s there will be (1000 + 10t ) L of liquid in the tank. But we're also removing 25 L from the tank per second, so there is a net "gain" of 10 - 25 = -15 L of liquid each second. So the volume of liquid in the tank at time t is (1000 - 15t ) L. Then the concentration of chlorine per unit volume is c (t ) divided by this volume.

So the amount of chlorine in the tank changes according to

$\dfrac{\mathrm dc(t)}{\mathrm dt}=-\dfrac{5c(t)}{200-3t}$

which is a linear equation. Move the non-derivative term to the left, then multiply both sides by the integrating factor 1/(200 - 5t )^(5/3), then integrate both sides to solve for c (t ):

$\dfrac{\mathrm dc(t)}{\mathrm dt}+\dfrac{5c(t)}{200-3t}=0$