Answer:
\large \boxed{\textbf{Bowl = 300 g; cup = 200 g}}
Step-by-step explanation:
Let b = the mass of a bowl
and c = the mass of a cup
We have two conditions:

Calculations:

Check:

OK.
Answer:
Step-by-step explanation:
We have plane 1 flying SW for 4 hours at a rate of 415 mph. The distance he covers using the d = rt formula for distance, is 415(4) = 160 miles.
We also have plane 2 flying directly east (along the x-axis) for 4 hours at 327 mph. The distance he covers using the d = rt formula for distance, is 327(4) = 1308 miles. The angle in between them at this point is 135 degrees, and what we need to find is the length of the vector connecting the 2 planes. IF this was right triangle trig that distance would be the hypotenuse and we could solve for it using Pythagorean's Theorem. BUT it is NOT a right triangle, so we have to find some other means with which to solve for that length. We will use the Law of Cosines to do this.
which simplifies a bit to

If you add all of that together, you'll get
and you'll take the square root of that to get that the distance between the 2 planes after 4 hours is
2745 miles
Answer:
I,
Step-by-step explanation:
Part e because I did it and got it right on the test txt me if u need help