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nataly862011 [7]
3 years ago
10

Scanner scanned 72 photos in 8 min. If it scans photos at a constant rate. It can scan ____ photos in 23 mins

Mathematics
1 answer:
jeyben [28]3 years ago
6 0
Rate: 72/8 = 9 photos/min

23 mins -> 9 * 23  = 207 photos
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If the fraction 408/x-10 is equivalent to -24 find the value of x
erik [133]

Answer:

Step-by-step explanation: yes it is that is how you do it

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3 years ago
Find a three digit number. The tens digit is 3 time the hundreds digit. The sum of the digits is 15. If you reverse the digits,
tresset_1 [31]

Answer:

number = 267

Step-by-step explanation:

i am a 3 digit number divisible by 3.

100a + 10b + c

my tens digit is 3 times as great as my hundreds digit

b = 3a, from this we know a = 1, 2, 3, then b = 3, 6, 9

and the sum of my digits is 15.

a + b + c = 15

if you reverse my digits i am divisible by 6 and 3

100c + 10b + a

this is a logic problem, an equation won't help us here

From the given information b = 3a, and the sum of the 3 digits = 15, we have:

1 3 ___; three single digits can't add up to 15

2 6 _7_; this has to be the number

3 9 _3_; reverse number is not different

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3 0
3 years ago
What is the percentage of 13/16
Fed [463]
13/16= 0.8125

Hope this helps!
7 0
3 years ago
Read 2 more answers
The total cost of painting of four walls of a square hall at Rs. 40 per sq. m. is Rs. 12000. If the hall contains 600 m³ of air,
astra-53 [7]

Answer:

The height of the hall is 9.375 meters

Step-by-step explanation:

The rate at which the walls of the square hall are painted, R = Rs. 40 per sq. m.

The total cost of painting the square hall, C = Rs. 12,000

The volume of air contained in the hall, V = 600 m³

The surface area of the four walls of the hall, A = C/A

∴ A = Rs. 12,000/(Rs. 40/m²) = 300 m²

Let 's' represent the length of sides of the square hall, and let 'h' represent the height of the square wall, we have;

The volume of the hall, V = s² × h

The surface area of the wall, A = 4 × s × h

Therefore, we get;

A = 300 = 4 × s × h

V = 600 = s² × h

V/A = 600/300 = 2 = s² × h/(4 × s × h) = s/4

s/4 = 2

s = 4 × 2 = 8

The side length of the square hall, s = 8 m.

From the area, A = 4 × s × h, we get;

A = 300 = 4 × 8 × h

h = 300/(4 × 8) = 9.375

The height of the hall, h = 9.375 m.

8 0
3 years ago
I need help on this problem someone please help
Hatshy [7]
The outlier is a because it is the most different value compared to the rest.
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3 years ago
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