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3 years ago

PLEASE HELP WILL GIVE BRAINLIEST! ASAP please!

Mathematics

1 answer:

ZanzabumX [31]3 years ago

3 0

Answer:

14. T (0.75,-1)

U (0.75, 1.25)

V (-0.75, 1.25)

15. W (-0.75, -1)

16. Coordinates with x =0 are on the y-axis not the x-axis.

Step-by-step explanation:

14. The (x,y) points are written using the x value and y value for the coordinate.

T (0.75,-1)

U (0.75, 1.25)

V (-0.75, 1.25)

15. The fourth vertex of the rectangle called W will need to be at the same level as T and lined up with V.

W (-0.75, -1)

16. Coordinates with x =0 are on the y-axis not the x-axis.

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Suppose a triangle has sides 3, 4, and 6. Which of the following must be true? A: The triangle in question is not a right triang

Talja [164]

Answer:

A: The triangle in question is not a right triangle.

Step-by-step explanation:

If the triangle is a right triangle, then the Pythagorean theorem would hold

a^2 + b^2 = c^2

3^2 + 4^2 = 6^2

9+16 = 36

25 = 36

This is not true so this is not a right triangle

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3 years ago

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A cone has a radius of 3 and a height given by the expression 2a. Which expression represents the volume of the cone?

DiKsa [7]

V=(1/3)hπr^2 where h=height and r=radius
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radius=3
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3 years ago

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The length of a swimming pool is 3 feet longer than it’s width. The swimming pool is surrounded by a deck that is 2 feet wide an

Firlakuza [10]

Answer:

The Length of swimming pool is 8.35 feet

The width of swimming pool is 5.35 feet

Step-by-step explanation:

Given as :

The length of swimming pool is 3 feet longer that its width

Let The width of swimming pool = w feet

So, The Length of swimming pool = L = (w + 3) feet

Now, The swimming pool is surrounded by deck of 2 feet wide

The width of deck = w' = w + 2 + 2 = (w + 4) feet

The area of deck = 116 feet²

The length of deck = L' = L + 2 + 2 = (L + 4) feet

So, L' = (w + 3 + 4) feet

I.e L' = (w + 7) feet

∵ The area of deck = 116 feet²

So , L' × w' = 116 feet²

(w + 7)× (w + 4) = 116

Or, w² + 4 w + 7 w + 28 = 116

Or, w² + 11 w - 88 = 0

Solving the quadratic equation as

ax² + bx + c = 0

So, w = $\dfrac{-b\pm \sqrt{b^{2}-4\times a\times c}}{2\times a}$

Or, w = $\dfrac{-11\pm \sqrt{11^{2}-4\times 1\times (-88)}}{2\times 1}$

Or, w = $\dfrac{-11\pm \sqrt{473}}{2}$

or, w = $\dfrac{-11\pm 21.7}{2}$

or, w = 5.35 , -16.35

The width of swimming pool = w = 5.35 feet

The Length of swimming pool = L = (5.35 + 3) feet = 8.35 feet

Hence, The Length of swimming pool is 8.35 feet

And The width of swimming pool is 5.35 feet

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iVinArrow [24]

Answer:

Step-by-step explanation:

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mariarad [96]

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Hope this can help.

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3 years ago

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PLEASE HELP WILL GIVE BRAINLIEST! ASAP please! ​

PLEASE HELP WILL GIVE BRAINLIEST! ASAP please!