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Lady_Fox [76]
3 years ago
9

WILL MARK BRAINLIEST!!!!!!!!! Can anyone help me with this.....There are multiple answers that need to be chosen

Mathematics
2 answers:
fomenos3 years ago
6 0

Answer:

1st, 3rd, 5th

Step-by-step explanation:

tamaranim1 [39]3 years ago
3 0
The first one then the third one and also the fifth one
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Demand for Tablet Computers The quantity demanded per month, x, of a certain make of tablet computer is related to the average u
soldier1979 [14.2K]

x = f ( p ) = \frac { 100 } { 9 } \sqrt { 810,000 - p ^ { 2 } } } \\\\ \qquad { p ( t ) = \dfrac { 400 } { 1 + \dfrac { 1 } { 8 } \sqrt { t } } + 200 \quad ( 0 \leq t \leq 60 ) }

Answer:

12.0 tablet computers/month

Step-by-step explanation:

The average price of the tablet 25 months from now will be:

p ( 25) = \dfrac { 400 } { 1 + \dfrac { 1 } { 8 } \sqrt { 25 } } + 200 \\= \dfrac { 400 } { 1 + \dfrac { 1 } { 8 } \times 5 } + 200\\\\=\dfrac { 400 } { 1 + \dfrac { 5 } { 8 } } + 200\\p(25)=\dfrac { 5800 } {13}

Next, we determine the rate at which the quantity demanded changes with respect to time.

Using Chain Rule (and a calculator)

\dfrac{dx}{dt}= \dfrac{dx}{dp}\dfrac{dp}{dt}

\dfrac{dx}{dp}= \dfrac{d}{dp}\left[{ \dfrac { 100 } { 9 } \sqrt { 810,000 - p ^ { 2 } } }\right] =-\dfrac{100}{9}p(810,000-p^2)^{-1/2}

\dfrac{dp}{dt}=\dfrac{d}{dt}\left[\dfrac { 400 } { 1 + \dfrac { 1 } { 8 } \sqrt { t } } + 200 \right]=-25\left[1 + \dfrac { 1 } { 8 } \sqrt { t } \right]^{-2}t^{-1/2}

Therefore:

\dfrac{dx}{dt}= \left[-\dfrac{100}{9}p(810,000-p^2)^{-1/2}\right]\left[-25\left[1 + \dfrac { 1 } { 8 } \sqrt { t } \right]^{-2}t^{-1/2}\right]

Recall that at t=25, p(25)=\dfrac { 5800 } {13} \approx 446.15

Therefore:

\dfrac{dx}{dt}(25)= \left[-\dfrac{100}{9}\times 446.15(810,000-446.15^2)^{-1/2}\right]\left[-25\left[1 + \dfrac { 1 } { 8 } \sqrt {25} \right]^{-2}25^{-1/2}\right]\\=12.009

The quantity demanded per month of the tablet computers will be changing at a rate of 12 tablet computers/month correct to 1 decimal place.

8 0
3 years ago
The distance between Anubhav’s school and his house is 45 km. He started from his house for school at 7:00 am and covered 30 km
8_murik_8 [283]

Answer:

45 km/h

Step-by-step explanation:

In the first part of the trip, he already covered 30 km so we can subtract that from the total distance

45 - 30 = 15

This means he has 15 km to go

He also took an hour, or 60 minutes, to get to school. We subtract the time spent of the first part and time spent talking to a friend from the 60 minutes

60 - 35 = 25

25 - 5 = 20

He took 20 minutes to cover the second part of the journey

Speed = distance/time

15/20 = 0.75

He covered 0.75 km per MINUTE

to find it in km/h, we just multiply the number by 60

0.75 x 60 = 45

6 0
3 years ago
Read 2 more answers
00:00
vaieri [72.5K]

Answer:

(D)What did Micah eat for lunch yesterday?

Step-by-step explanation:

A statistical question is a question for which the expected response varies. That is, we do not expect to get a single answer. Out of the given options,

Option D is not a valid statistical question as the response to the question will always be the same for a particular day,

If Micah ate cheesecakes for lunch yesterday, asking repeated times will not change the response.

6 0
3 years ago
PROBLEM #5
andrezito [222]

Answer:

12.5%

Step-by-step explanation:

80 - 70 = 10

10 / 80 = 0.125

Convert decimal to percent.

0.125 = 12.5%

5 0
3 years ago
The decibel level of sound in a quiet office is 10−6watts/m2.
Liono4ka [1.6K]
I don’t understand your question can you explain it more
4 0
3 years ago
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