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3 years ago

Find two numbers whose sum is 50 and whos difference is 22

Mathematics

2 answers:

solong [7]3 years ago

8 0

I think someone else answered but it’s 36 and 14

pentagon [3]3 years ago

5 0

Answer:

36 and 14

Step-by-step explanation:

Create an equation

x+x-22=50

Combine like terms

2x-22=50

Add 22 on both sides

2x=72

divide 72 by 2

x=36

subtract 22 from 36

14+36=50

Hope this helps! :P

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What is the absolute value of 1/2?

harina [27]

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3 years ago

A car is being driven at a rate of 40 ft/sec when the brakes are applied. The car decelerates at a constant rate of 10 ft/sec2.

IRISSAK [1]

Answer:

80 feet

Step-by-step explanation:

Given:

Initial speed of the car ( $v_0$ ) = 40 ft/sec

Deceleration of the car ( $\frac{dv}{dt}$ ) = -10 ft/sec²

Final speed of the car ( $v_x$ ) = 0 ft/sec

Let the distance traveled by the car be 'x' at any time 't'. Let 'v' be the velocity at any time 't'.

Now, deceleration means rate of decrease of velocity.

So, $\frac{dv}{dt}=-10\ ft/sec^2$

Negative sign means the velocity is decreasing with time.

Now, $\frac{dv}{dt}=\frac{dv}{dx}(\frac{dx}{dt})$ using chain rule of differentiation. Therefore,

$\frac{dv}{dx}\cdot\frac{dx}{dt}= -10\\\\But\ \frac{dx}{dt}=v.\ So,\\\\v\frac{dv}{dx}=-10\\\\vdv=-10dx$

Integrating both sides under the limit 40 to 0 for 'v' and 0 to 'x' for 'x'. This gives,

$\int\limits^0_{40} {v} \, dv=\int\limits^x_0 {-10} \, dx\\\\\left [ \frac{v^2}{2} \right ]_{40}^{0}=-10x\\\\-10x=\frac{0}{2}-\frac{1600}{2}\\\\10x=800\\\\x=\frac{800}{10}=80\ ft$

Therefore, the car travels a distance of 80 feet before stopping.

4 0

3 years ago

Indicated operation

lutik1710 [3]

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3 years ago

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stepan [7]

Answer:

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3 years ago

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attashe74 [19]

Answer:

3.75 cu. cm.

Step-by-step explanation:

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= 1/8 x 30

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7 0

3 years ago