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zloy xaker [14]
4 years ago
12

Eight students in a small class made the test scores shown in the table. What was the mean absolute deviation for the class?

Mathematics
1 answer:
Alex4 years ago
8 0
The mean is unknown because you did not attach any pictures or insert the values
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What is the radius of each semicircle in the following composite figure?
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Hope this helps!

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Simon used mixed nuts and other ingredients to make 5 cups of trail mix. The chart below shows the nutritional facts for mixed n
Reptile [31]

Answer:

Multiply 3 times 5.25

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3 years ago
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Identify the pair of events as dependent or independent. An odd-numbered problem is assigned for homework, and an even-numbered
S_A_V [24]

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As the homework and test are two separate things, selecting an odd or even number on either of them will not affect the probability of selecting an odd or even number on the other.

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5 0
3 years ago
Which expressions are equivalent to \dfrac{4^{-3}}{4^{-1}} 4 −1 4 −3 ​ start fraction, 4, start superscript, minus, 3, end super
Slav-nsk [51]

Answer:

\dfrac{4^{-3}}{4^{-1}} = \dfrac{4^{1}}{4^{3}}

\dfrac{4^{-3}}{4^{-1}} = \dfrac{1}{4^{2}}

Step-by-step explanation:

Given

\dfrac{4^{-3}}{4^{-1}}

Required

Choose equivalent expressions

Choosing the first answer:

\dfrac{4^{-3}}{4^{-1}}

Split expressions

4^{-3} * \frac{1}{4^{-1}}

Apply laws of indices: (a^{-b} = \frac{1}{a^b})

\frac{1}{4^3} * \frac{1}{4^{-1}}

Apply laws of indices: (a^{-b} = \frac{1}{a^b})

\frac{1}{4^3} * \frac{1}{1/4}

\frac{1}{4^3} * \frac{4^1}{1}

\frac{4^1}{4^3}

Hence:

\dfrac{4^{-3}}{4^{-1}} = \dfrac{4^{1}}{4^{3}}

Choosing the second:

\dfrac{4^{-3}}{4^{-1}}

Apply law of indices: (\frac{a^m}{a^n} = a^{m-n})

So,

\dfrac{4^{-3}}{4^{-1}} = 4^{-3-(-1)}

\dfrac{4^{-3}}{4^{-1}} = 4^{-3+1)}

\dfrac{4^{-3}}{4^{-1}} = 4^{-2}

Apply law of indices: (a^{-b} = \frac{1}{a^b})

So:

\dfrac{4^{-3}}{4^{-1}} = \dfrac{1}{4^{2}}

4 0
3 years ago
I need help plz!!!!!!
GrogVix [38]

Answer:

put -2 in -2    /   put -2 again in same spot and again just do it for 3 times then 1/3 in the middle of 0 and -2 but a bit closer to the -2

Step-by-step explanation:

8 0
3 years ago
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