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2 answers:
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Answer:
0.0351478382 (To be precise)
Step-by-step explanation: Can I get brainliest? Thanks
1. Normal Distribution --> Z ~ (0,1^2)
2. Use normalcdf(lower bound, upper bound, μ, σ) function on a graphing calculator
P(Z≥103.53) = normalcdf(103.53, 1e99 [default], 80, 13)
P(Z≥103.53) ≈ 0.03
3. μ+σ ≈ 13.59% According to Z-distribution chart
80+13=93
So about 93 exceed only the top 16% (estimated answer not exact)
