Answer: 56 large cars and 86 small cars.
Step-by-step explanation:
Let's call:
: the number of large cars.
: the number of small cars.
Then, you can set up the following system of equations:
You can use the Elimination Method:
- Multiply the first equation by -4.0
- Add both equations.
- Solve for l.
≈
Substitute 
into one of the original equations and solve for <em>s:</em>
<em> </em>
-9x^3-72x^2+36=3x^3+x^2-3x+8 Add 9x^3 to both sides.
-72x^2 + 36 = 3x^3 + 9x^3 + x^2 - 3x + 8 Add 72x^2 to both sides
36 = 12x^3 + 73x^2 - 3x + 8 Subtract 36 from both sides.
0 = 12x^3 + 73x^2 - 3x - 28
It does factor, but it is not very nice.
(x + 6.06)(x - 6.09)(x + 0.632)
If there is any kind of error please report it in a note below.
Answer:
6
Step-by-step explanation:
total no. of seats = 22 x 4 = 88
total no. of seats occupied = 19 * 4 + (22-19)*4/2 = 76 + 6 = 82
no. of empty seats = 88 -82 = 6
The answer's 2.2
I'm sorry I can't show you, but LaTex doesn't allow you to show short division.
You can find out how to do it here, on Wikipedia's page. https://www.wikiwand.com/en/Short_division
Last one i think
x=0 or x=6
