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3 years ago

11

A group of tourists go on a tour. the tour guide rents 15 vans. each van holds 9 tourists write a division problem that can be u

sed to find the number of vans needed to carry the tourists. them solve

1 answer:

Brut [27]3 years ago

8 0

15/9 = 1.66 = 1.7 so, technically 2 vans will need to be rented.

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Help me solve,Brainlist for first to answer

Vanyuwa [196]

Answer:

(i) the other two sides are 6 and 6 $\sqrt{2}$

(ii) the other two sides are $\frac{4}{3} and \frac{8}{3}$

Step-by-step explanation:

(i) Sine: sin(θ) = Opposite ÷ Hypotenuse

Cosine: cos(θ) = Adjacent ÷ Hypotenuse

Tangent: tan(θ) = Opposite ÷ Adjacent

Here adjacent side = 6

opposite side = d

angle = 45°

other angles are 90° and 45°

tan (45) = Opposite ÷ Adjacent

1 = d ÷ 6

∴ d = 6 × 1 = 6

so opposite side = 6

Hypotenuse ² = opposite side ² + adjacent side²

= 6² + 6²

= 36 + 36

= 72

hypotenuse = $\sqrt{72}$

= 6 $\sqrt{2}$

the other two sides are 6 and 6 $\sqrt{2}$

(ii) here adjacent side = 4√3

angle = 30°

other angles are 90° and 60°

opposite side = d

tan ( 30) = opposite ÷ adjacent

$\frac{1}{\sqrt{3}}$ = d ÷ 4√3

$\frac{1}{\sqrt{3}}$ = d × ( $\frac{\sqrt{3}}{4}$ )

3 d = 4

therefore d = $\frac{4}{3}$

therefore opposite side = $\frac{4}{3}$

Hypotenuse ² = opposite side ² + adjacent side²

=( $\frac{4}{3}$ )² +( $\frac{4}{\sqrt{3}}$ )²

= $\frac{64}{9}$

therefore hypotenuse = $\sqrt{\frac{64}{9}}$

= $\frac{8}{3}$

the other two sides are $\frac{4}{3} and \frac{8}{3}$

7 0

3 years ago

NO LINKS OR ANSWERING QUESTIONS YOU DON'T KNOW!!! THIS IS NOT A TEST OR AN ASSESSMENT!! Please help me with these math questions

Art [367]

Answer:

See below

Step-by-step explanation:

3. What are two ways that a vector can be represented?

Considering a vector $\vec{v}$ in some vector space $\mathbb R^n$ we have

$\vec{v} = \langle a,b\rangle$

This is the component form. I don't like that way. It is probably used in high school, but

$\vec{v} = \begin{pmatrix} a\\ b\\ \end{pmatrix}$

is preferable because the inner product on $\mathbb R^n$ is defined to be

$\langle a,b\rangle := \sum_{i = 1}^n a_i b_i$

You can also write it using linear form such as $\vec{v} = 2i+2j$

4.

For this question, I think you meant

vectors

$\vec{u_1} = (-8, 12)$

$\vec{u_2} = (13, 15)$

Once

$\cos(\theta)=\dfrac{\vec{u_1} \cdot\vec{u_2}}{||\vec{u_1}||||\vec{u_2}||}$

Considering that the dot product is

$\vec{u_1}\cdot \vec{u_2} = (-8)\cdot 13 + 12\cdot 15 = -104+180= 76$

and the norm of $\vec{u_1}$ is $||\vec{u_1}|| = \sqrt{(-8)^2 + 12^2} = \sqrt{64 + 144}= \sqrt{208}$

and the norm of $\vec{u_2}$ is $||\vec{u_2}|| = \sqrt{13^2 + 15^2} = \sqrt{169 + 225}= \sqrt{394}$

Thus,

$\cos(\theta)=\dfrac{76}{\sqrt{208} \sqrt{394}} = \dfrac{19}{\sqrt{13}\sqrt{394}}=\dfrac{19}{\sqrt{5122}}$

$\therefore \theta = \arccos \left(\dfrac{19}{\sqrt{5122}} \right)$

3 0

2 years ago

If it takes 20 seconds to ring up a customer how many items are being purchased

valkas [14]

Answer: proly like 2

Step-by-step explanation:

Because you have to pay and scan!

5 0

3 years ago

nexus9112 [7]

The answer is 66 units

6 0

3 years ago

Read 2 more answers

a 2014 mustang originally costs $25000.00 and depreciates at a rate of 8% per year. What is the cost of the car after 7 years?

frutty [35]

$11,000 will bet the cost in 7 years

Given:

Original cost: $25,000

Depreciation rate: 8%

Term: 7 years

Formula for Depreciation:

A = C ( 1 - ( r ) (t) )

A = Future Value

C = Original Cost

r = rate

t = term

Solution:

Substitute the given values to the formula for depreciation.

A = $25,000( 1 - ( 0.08)(7))

A = $25,000( 1 - .56 )

A = $25,000(0.44 )

A = $11,000

8 0

2 years ago