Standard form of an equation is ax + by = c, which in this case is 5x + 3y = 14, or B.
Answer:
r = i + j + (-2/3)(3i - j)
Step-by-step explanation:
Vector Equation of a line - r = a + kb ; where r is the resultant vector of adding vector a and vector b and k is a constant
if a = i + j ; b = t(3i - j) and r = -i +s(j)
for this to be true all the vector components must be equal
summing i 's
i + 3ti = -i; then t = -2/3
j - tj = sj; then s = 1-t; substitue t; s=1+2/3 = 5/3
so r = i + j + (-2/3)(3i - j) which will symplify to -i + 5/3j
Answer:under is answer
Step-by-step explanation:
5/8+3/4=11/8 then,-2/3-5/6=-3/2
Since the triangle is a right triangle at point B, then line AB is perpendicular to line BC.
For perpendicular lines, the product of their slopes is -1.
Slope of AB = (5 - 0)/(2 - 5) = 5/-3 = -5/3
Slope of BC = (y - 5)/(7 - 2) = (y - 5)/5
-5/3(y - 5)/5 = -1
-5(y - 5)/15 = -1
-5(y - 5) = -15
y - 5 = 3
y = 3 + 5 = 8
Therefore, the y-coordinate of point C is 8.
