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skad [1K]
3 years ago
10

0.00569÷(3×10^3)^2 help me

Mathematics
1 answer:
Kazeer [188]3 years ago
3 0
I got 6.22222222222E-10
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50 centimeters times blank = blank pounds
slava [35]

Answer:

0.11

Step-by-step explanation:

I found that out by multiplying the centimeters by pounds

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Round 703 to the nearest hundred
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703 rounded to the nearest hundred is 700
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Whole proofs page for 50 points (serious answers only or report and 1 star)
lord [1]

The reasons that can be used to complete the two column table used to prove the required expressions are;

1. ∆ABD Cong. ∆CBE Side-Angle-Side, SAS, rule of congruency

2. ∆ABC cong. ∆EDC Angle-Side-Angle, ASA, rule of congruency

<h3>Which postulates can be used to complete the tables?</h3>

1. Statements Reasons

1) <A = <C Given

2) AB = BC. Congruent sides of isosceles triangle

3) AE Cong. DC. Given

4) AE = DC. Definition of congruency

5) ED Cong. ED. Reflexive property of equality

6) AE + ED = DC + ED Addition property of equality

7) AE + ED = AD, DC + ED = CD Addition property of equality

8) AD = ED, Substitution property of equality

9) AD Cong. ED Definition of congruency

10) ∆ABD Cong. ∆CBE Side-Angle-Side, SAS, rule of congruency

2. Statements Reasons

1) AB || DE Given

Midpoint of BD = C Given

2) <ABC Cong. <EDC Alternate angles formed by parallel lines

3) BC Cong. CD Definition of midpoint

4) <ACB Cong. <DCE Vertical angle theory

5) ∆ABC cong. ∆EDC Angle-Side-Angle, ASA, rule of congruency

Learn more about the rules of congruency here:

brainly.com/question/4186813

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3 0
2 years ago
If jen has 2 meters of taffy and 3 friends but she wants to split her taffy equally amongst her friends how many pieces of taffy
Reptile [31]
Well 2 ÷ 3 = 0.66666667
Each friend would get 0.7 taffy
6 0
4 years ago
Two forces with magnitudes of 150 and 75 pounds act on an object at angles of 30° and 150°, respectively. Find the direction and
kompoz [17]
Answer:

Magnitude: 121.35 pounds

Direction: 21.64°

Explanation:

1) Decompose each force into its x - y components.

2) Force 1, F1: 140 pounds at angle of 30°

x-component: F1,x

F1, x = F1 *cos(30°) = 140 pounds * cos(30°) = 121.24 pounds

y-component: F1,y

F1,y = F1 * sin(30°) = 140 pounds * sin(30°) = 70 pounds.

3) Force 2, F2: 75 poounds at 150°

x-component: F2,x

F2,x = F2 * cos(150°) = 75 pounds * cos(150°) = - 64.95 pounds

y-component: F2,y

F2,y = F2 * sin(150°) = 75 pounds * sin(150°) = 37.5 pounds

4) Resultant Force, Fr

x-component: Fr,x

Fr,x = F1,x + F2,x = 121.24 pounds - 64.95 pounds = 56.29 pounds

y-component: Fr,y

Fr,y = F1,y + F2,y = 70 pounds + 37.5 pounds = 107.5 pounds

4.1) magnitude

|Fr| = √ [ (56.29 pouns)^2 + (107.5 pounds)^2 ] = 121.35 pounds.

4.2) direction

tan(α) = Fr,y / Fr,3 = 56.29 pounds / 107.5 pouns = 0.5236

=> α = arctan(0.5236) = 27.64 °


5 0
4 years ago
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