Aanya wrote the four equations that are shown below. She examined them, without solving them, to determine which has exactly one

Question

2 years ago

9

solution. Which of aanya's equations has exactly one solution
A:6x-8=4(x-2)+2x
B:3(x-1)+2x=3(x-1)+2
C:7x+2-x=6(x+2)
D:4(x+3)+x=5(x+1)+7

2 answers:

mojhsa [17] · Answer 1 · 2022-10-11T16:45:58+03:00

Answer:

B:3(x-1)+2x=3(x-1)+2

Step-by-step explanation:

Aanya wrote the four equations that are shown below.

We need to check each equation and see which equations have same coefficient of x terms on both sides of equation.

A: 6x-8=4(x-2)+2x

Distribute 4 inside the parenthesis

6x-8=4x- 8+2x

We know 4x + 2x is 6x. So, both sides we have 6x. Hence no solution for this equation.

B:3(x-1)+2x=3(x-1)+2

Distribute 3 inside the parenthesis

3x - 3 + 2x = 3x - 3 + 2

5x - 3 = 3x- 3 + 2

Coefficient of x are not same on both sides. So this equation has exactly one solution.

C:7x+2-x=6(x+2)

Distribute 6 inside the parenthesis

6x + 2= 6x + 12

Both sides we have 6x. Hence no solution for this equation.

D:4(x+3)+x=5(x+1)+7

Distribute 4 and 5 inside the parenthesis

5x + 12= 5x + 5+ 12

Both sides we have 5x. Hence no solution for this equation.

Marianna [84] · Answer 2 · 2022-10-11T19:10:30+03:00

4 0

Answer:

The actual answer is C.

Hope I helped, it’s right on Ed genuity

Step-by-step explanation: