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sveticcg [70]
3 years ago
14

WILL GIVE BRAINLIEST

Biology
2 answers:
Montano1993 [528]3 years ago
7 0
The second one due to the fact that pioneer plants come in much later
rosijanka [135]3 years ago
4 0

Answer:

B

Explanation:

5,1,2,3,4

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Goshia [24]

Explanation:

Cell Cycle Regulators. The cell cycle controls replication and apoptosis, prevents uncontrolled cell division (tumor formation), and may involve detection and repair of damage to DNA. ... Sigma offers a host of cell cycle regulators such as antimitotics, mitotic inhibitors, and cytokinesis inhibitors.

8 0
3 years ago
Define atomic number, atomic weight and atomic mass.
lozanna [386]
Atomic number shows the number of protons in the nucleus of an atom.
Atomic weight shows the is an another term for atomic mass, which means <span>It is approximately equivalent to the number of protons and neutrons in the atom (the mass number) or to the average number allowing for the relative abundances of different isotopes.</span>
6 0
3 years ago
Part A - The glucose-sodium cotransporter
Ulleksa [173]
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5 0
3 years ago
A record turntable is rotating at 33 rev/min. A watermelon seed is on the turntable 7.8 cm from the axis of rotation. (a) Calcul
Novosadov [1.4K]

Given data:

● Angular velocity of the turntable ω = 33 rev/min

Therefore,

ω = 33 rev/min

ω = 33rev/min × 2π rad/rev × 1 min/60 sec = 3.45 rad/s

● The distance of the watermelon seed from the axis of rotation r = 7.8 cm = 0.078 m

● μs = the coefficient of static friction

Section a:

The seed is undergoes circular motion and it is been effected by centripetal acceleration.

ac = rω^2

ac = 0.078 × 3.45^2

ac = 0.9284 m/s^2

Therefore,

the centripetal acceleration of the seed is 9.274 m/s^2

Section b:

If the seed is observed not to slip at the course of the circular motion, then the supplied frictional force given by the seed and surface of turntable would at least be equivalent to the centripetal force working on the seed.

Centripetal Force = Frictional Force

mrω^2 = μsmg

μs = rω^2 /g

μs = 0.078 × 3.45^2

------------

9.81

μs = 0.09464

Thus,

the coefficient of static friction is 0.09464.

6 0
3 years ago
Which statements describe thigmotropism
anygoal [31]

Answer:

1,2,4,and 6

Explanation:

CAUSE I KNOW

6 0
3 years ago
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