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wolverine [178]
3 years ago
15

Evaluate the expression (-7) to the power of 3

Mathematics
2 answers:
Andrej [43]3 years ago
7 0
The answer is -343 she is correct
Goshia [24]3 years ago
3 0
-343 I think but I am not totally sure
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What values for theta (0≤theta≤2π) satisfy the equation?
Rufina [12.5K]

Answer:

Option (1)

Step-by-step explanation:

<em>For convenience sake, I will be omitting the arguments of the trig functions.</em>

3sin = sin - sqrt(3)

2sin = -sqrt(3)

sin = -sqrt(3)/2

So, the answer is 4pi/3 and 5pi/3.

4 0
2 years ago
What is 1.83333 as a fraction
earnstyle [38]

Answer:Para pasar el número decimal 1.83333 a fracción, siga los siguientes pasos:

Paso 1: Escriba el número como una fracción de 1 (uno):

1,83333 = 1,83333/1

Paso 2: Multiplica simultáneamente el numerador y el denominador por 10 tantas veces cuánto los dígitos después de la coma (separación entre la parte entera y la parte fraccionaria del número):

Como tenemos 5 números después de la coma, multiplique el numerador y el denominador por 100000. Así,

1,83333/1 = (1,83333 x 100000)/(1 x 100000) = 183333/100000.

Tenga en cuenta que multiplicar por 10 es el mismo que desplazar la coma a la derecha una posicion.

Una vez que esta fracción es irreductible, es decir, está en forma reducida, ya no podemos simplificarla. La respuesta es la fracción anterior.

Como el numerador es mayor que el denominador, tenemos una fracción IMPRORIA, entonces podemos expresarla como un NÚMERO separación, así 183333/100000 también es igual a 1 83333/100000 cuando se representa por un número mixto.

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
A box has four cards numbered 1, 2, 3, and 4
lora16 [44]
Sample space: H1, H2, H3, H4, T1, T2, T3, T4
All outcomes if the card is three: H3, T3
I was unclear about the last two parts of the question.
6 0
4 years ago
Eight is 34 more than the product of a number and 2 in number form
andre [41]

Answer:

8 = 34 + (n * 2) / 8 = (n * 2) + 34 ; n = -13

Step-by-step explanation:

In this question we have 2 numbers and a variable. The variable is "a number," which I have represented as "n" in my answer. As long as there is a letter in the spot of n, that is the correct answer- your assignment might have represented the variable differently.

When the question says "8 is" it is saying "8 is equal to." "Is" represents an equals sign in this equation. "More than" represents addition, or the sum of. "The product of" represents multiplication. "The product of a number and 2" means that we are multiplying n and 2 BEFORE adding it to 34, so we want to make sure to include those in parenthesis to signify that we do indeed solve that part of the equation first. As long as you know PEMDAS you should be fine here, but I prefer to add what the equation wants me to do first in parenthesis so that it's more readable. Since the order of numbers doesn't matter in addition, 34 can go both before and after "the product of n and 2."  

This gives us the equation "8 = 34 + (n * 2)," or the alternate "8 = (n * 2) + 34."

If you want to solve for N, you would need to subtract 34 from 8 and 34 itself, leaving -26 = (n * 2) or -26 = n(2). Then, since we're multiplying n by 2, we want to divide 2 by 2 to cancel it out, doing the same thing to -26. We are left with -13 = n, or n = -13.

3 0
3 years ago
Drag each tile to the correct box consider the given functions f,g and h place the tiles in order from least to greatest accordi
Alja [10]

Answer:

Step-by-step explanation:

By definition, the average rate of change of a function f over an interval [a,b] is given by

\dfrac{f(b)-f(a)}{b-a}

compute the quantity

\dfrac{f(3)-f(0)}{3}

for all the three function

Average rate of change of f:

We will simply use the table to check the values for f(3) and f(0):

\dfrac{f(3)-f(0)}{3}=\dfrac{10-1}{3} = 3

Average rate of change of g:

We will use the graph to to check the values for g(3) and g(0):

\dfrac{g(3)-g(0)}{3}=\dfrac{8-1}{3} = \dfrac{7}{3}

Average rate of change of h:

We can plug the values in the equation to get h(3) and h(0):

h(3)=3^2+3-6=9+3-6=6,\quad h(0)=0^2+0-6=-6

And so the average rate of change is

\dfrac{h(3)-h(0)}{3}=\dfrac{6-(-6)}{3} = 4

3 0
4 years ago
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