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2 years ago

Six less than xI'm in 8th

Mathematics

1 answer:

Fudgin [204]2 years ago

7 0

Answer

I found this. Does this help?

Step-by-step explanation:

If this is an inequality (6 is less than x, or 6 < x), then x is an integer or other value greater than 6.

The variable statement "6 less than x" is (x - 6)

This is a value (variable and constant) where the value of x is determined by an equation

such as x-6 = 4 (x is positive 2) or y = x-6 (y is 6 less than x).

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Answer:

The probability that a randomly selected component needs rework when it came from line A₁ is 0.3623.

Step-by-step explanation:

The three different assembly lines are: A₁, A₂ and A₃.

Denote <em>R</em> as the event that a component needs rework.

It is given that:

$P (R|A_{1})=0.05\\P (R|A_{2})=0.08\\P (R|A_{3})=0.10\\P (A_{1})=0.50\\P (A_{2})=0.30\\P (A_{3})=0.20$

Compute the probability that a randomly selected component needs rework as follows:

$P(R)=P(R|A_{1})P(A_{1})+P(R|A_{2})P(A_{2})+P(R|A_{3})P(A_{3})\\=(0.05\times0.50)+(0.08\times0.30)+(0.10\times0.20)\\=0.069$

Compute the probability that a randomly selected component needs rework when it came from line A₁ as follows:

$P (A_{1}|R)=\frac{P(R|A_{1})P(A_{1})}{P(R)}=\frac{0.05\times0.50}{0.069} =0.3623$

Thus, the probability that a randomly selected component needs rework when it came from line A₁ is 0.3623.

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2 years ago

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3 years ago

Sophie and Simon are peeling a pile of potatoes for lunch in the cafeteria. Sophie can peel all the potatoes by herself in 45 mi

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Short Answer: 18 minutes
Remark
The answer to this problem is less than the smallest time of the two people working together. that fact lets out C and D (38 minutes and 75 minutes). Now you have to choose 15 minutes and 18 minutes. There's a method. No guessing needed.

Givens
Let the time for Sophie = S
Let the time for Simon = M
Let the job to completion = 1
S = 45 minutes
M = 30 minutes

Step One
Convert minutes to hours.
45 minutes = 45 / 60 = 3/4 hour = 0.75 hour
30 minutes = 30 / 60 = 1/2 hour = 0.50 hour

Step Two
Set up the Equation
The formula is a form of job / hour.
Let the time = t that they both have to work

job = 1 in these problems.
1/S + 1/M = 1/t
1/0.75 + 1/0.5 = 1/t

Solve
1 ÷ 0.75 = 1.33333
1 ÷ 0.5 = 2

1.3333 + 2 = 3.33333
3.3333 = 1 / t Multlply both sides by t
3.3333*t = 1
t = 1 / 3.333333333
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1 hour = 60 minutes
0.3 hours = x Cross Multiply
x = 60 * 0.3
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Answer working together it took them 18 minutes <<<<<

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3 years ago

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Six less than xI'm in 8th ​

Six less than xI'm in 8th