Answer:
a= 31
b=92
c=44
Step-by-step explanation:
Answer:
landing on a shaded portion and landing on an even number
; landing on a shaded portion and landing on a number greater than 3
; landing on an unshaded portion and landing on an odd number
; and landing on an unshaded portion and landing on a number less than 2.
Explanation:
Mutually exclusive events are events that cannot occur at the same time. Our spinner has two grey sections, on 1 and 3; and two white sections, on 2 and 4.
This means that the spinner cannot land on a shaded (grey) portion and land on an even number at the same time, since the grey sections are numbered 2 and 4, both of which are even numbers.
The spinner also cannot land on a shaded (grey) portion and land on a number greater than 3 at the same time; this is because the only number greater than 3 on the spinner is 4, which is a white portion.
The spinner cannot land on an unshaded (white) portion and land on an odd number, since the white sections are labeled 2 and 4, which are both even.
The only number on the spinner less than 2 is 1, which is grey; this means the spinner cannot land on a number less than 2 and an unshaded (white) portion at the same time.
Answer:
90 degrees
Step-by-step explanation:
A circle circumscribed over a right triangle is the same as a circle circumscribed over a rectangle built from the extension of the right triangle.
That tells us that the hypotenuse is the diameter of the circle in that case.
Here, we can see a triangle that has the hypotenuse as the diameter of the circumscribed circle. We can infer that the triangle is a right triangle.
Answer:
a) The discriminant of the equation = - 44
b)The nature of the roots will be imaginary.
c) 
Step-by-step explanation:
Here, the given expression is 
or, 
Now the discriminant (D) of a quadratic equation 
D = 
Hence, the discriminant of the equation = - 44
As D< 0, so the roots will be imaginary.
Now,by quadratic formula : 
So, here 
So, either 
or,
Answer:
A ≈ 35.3 units²
Step-by-step explanation:
Calculate the radius CB using Pythagoras' identity in the right triangle.
CB² + AB² = AC²
CB² + 6² = 9²
CB² + 36 = 81 ( subtract 36 from both sides )
CB² = 45 = r²
Then area of quarter circle is
A = 
× πr² = × π × 45 ≈ 35.3
