Question

If the equation of a circle is (х-2)2 + (у- 6)2 = 4, it passes through point

Answer 1

To check if a point belongs to an equation, simply substitute x and y with the given values, and see if you get something true or false.

For example, for the first point, we can plug x = -4 and y = 6 to get

$(-4-2)^2 + (6- 6)^2 = 4 \iff (-6)^2=4 \iff 36=4$

which is false, so the point doesn't belong to the circle. Similarly, for the second point, we have

$(4-2)^2 + (6- 6)^2 = 4 \iff 2^2=4 \iff 4=4$

which is true, so the point belongs to the circle.

Keep going like this with the other 2 points.

Answer 2

Answer:

(2, 6)

Step-by-step explanation:

Circle passes through the point (2, 6).