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Drupady [299]
3 years ago
8

In the picture provided, right triangle ABC is drawn with a 72 degree angle. For right triangles with it an angle of 72 degrees

the ratio of the side opposite the 72 degree angle compared to the hypotenuse is 19/20. If the hypotenuse. AC has a length of 100 what is the length of the opposite side to 72° angleBC.​

Mathematics
1 answer:
anygoal [31]3 years ago
6 0

Answer:

105,3≈105

Step-by-step explanation:

sin 72°=19/20

sin 72°=100/x

x=(20*100)/19=105,3

x=BC

x- is hypotenuse

i calculated with calculator

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4\sqrt{10}

Step-by-step explanation:

Perimeter of the rhombus, STAR, is the sum of the length of all it's 4 sides.

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T(2, 3)

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Length of each side can be calculated using the distance formula given as d = \sqrt{x_2 - x_1)^2 + (y_2 - y_1)^2}

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T(2, 3) => (x2, y2)

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TA = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}

T(2, 3) => (x1, y1)

A(3, 0) => (x2, y2)

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AR = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}

A(3, 0) => (x1, y1)

R(0, -1) => (x2, y2)

AR = \sqrt{(0 - 3)^2 + (-1 - 0)^2}

AR = \sqrt{(-3)^2 + (-1)^2} = \sqrt{9 + 1} = \sqrt{10}

RS = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}

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S(-1, 2) => (x2, y2)

RS = \sqrt{(-1 - 0)^2 + (2 -(-1))^2}

RS = \sqrt{(-1)^2 + (3)^2} = \sqrt{1 + 9} = \sqrt{10}

Perimeter = ST + TA + AR + RS

Perimeter = \sqrt{10} + \sqrt{10} + \sqrt{10} + \sqrt{10} = 4\sqrt{10}

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