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3 years ago

If h(x) = 4x − 8 and j(x) = −x, solve h[j(3)] and select the correct answer below. (1 point) −20 −36 1 4

Mathematics

2 answers:

nadya68 [22]3 years ago

4 0

Answer:

Correct answer is:

-20

Step-by-step explanation:

h(x) = 4x − 8 and j(x) = −x

We have to solve h[j(3)]

j(3)= -3

So, h[j(3)]=h[-3]

= 4(-3)-8

= -12-8

= -20

Hence, Correct answer is:

-20

Nostrana [21]3 years ago

3 0

Answer:

h[j(3)] = -20

Step-by-step explanation:

We need h(j(3)). First find j(3)

j(x) = -x, so

j(3) = -(3) = -3

Now find h(-3)

h(x) = 4x - 8, so

h(-3) = 4(-3) - 8

h(-3) = -12 - 8 = -20

So h[j(3)] = -20

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Troy and Lisa were shopping for school supplies. Each purchased different quantities of the same notebook and thumb drive. Troy

MaRussiya [10]

Answer:

The cost of each notebook is $3 and the cost of each thumb drive is $14.

Step-by-step explanation:

In order to solve this question we will attribute variables to the notebook and thumb drive. The price of a notebook we will call "x" and the price of a thumb drive will be "y". We now can create equations that represents the total amount spent by each person on these items. To do that we need to take the amount of each item that was bought and multiply it by it's price.

For Troy:

4*x + 6*y = 96

For Lisa:

2*x + 4*y = 62

We now have a system of equations and we can solve them by isolate one of he variables in one of the equations and using that value on the other. Using the second equation we have:

2*x + 4*y = 62

4*y = 62 - 2*x

y = 15.5 - 0.5*x

Using this expression on the first equation:

4*x + 6*(15.5 - 0.5*x) = 96

4*x + 93 - 3*x = 96

x = 96 - 93 = 3

We can now find the value of y:

y = 15.5 - 0.5*(3) = 14

The cost of each notebook is $3 and the cost of each thumb drive is $14.

7 0

2 years ago

GIVING BRANLIEST!!!

Anastasy [175]

Answer:

6, 26

Step-by-step explanation:

because x is 6 so itll be -3(6)=-8

-3 times 8 is -26

y=-26

4 0

3 years ago

A recent college graduate is planning to take the first three actuarial examinations in the coming summer. She will take the fir

erica [24]

Answer:

(a) 0.7

(b) $\frac 13$

Step-by-step explanation:

Let $E_1, E_2,$ and $E_3$ be the events of passing the 1st, 2nd, and 3rd exam individually.

Given that $P(E_1)=0.9\;\cdots(i)$

where $P(E_1)$ denotes the probability of passing the 1st exam.

Condition for passing the second exam is, at first, the candidate must have to pass the 1st exam.

So, $P\left(\frac{E_2}{E_1}\right)=0.8\;\cdots(ii)$

where $P(E_2/E_1)$ denotes the probability of passing the 2nd exam when she already passed the 1st exam (given, 0.8).

Similarly, as the conditional probability of passing the 3rd exam is 0.7, and the condition for this is, at first, she must have to pass the 1st and 2nd exam. i.e,

$P\left(\frac{E_2}{P(E_2/E_1)}\right)=0.7\;\cdots(iii)$

(a) For passing all the exams, the condition is, at first, she has to pass the 1st and 2nd exam, then she has to pass the 3rd exam too. The probability for this conditional has been given as 0.7.

So, the probability that she passes all three exams is 0.7.

(b) Given that she didn't pass all three exams that means she either failed in 1st exam or she passed the 1st and failed in 2nd exam or she passed both 1st and 2nd but failed in the 3rd exam.

Let F be the event that she didn't pass all three exams. So,

$P(F)=(1-P(E_1))+\left(1-\frac{P(E_2)}{P(E_1)}\right)+\left(1-\frac{P(E_2)}{P(E_2/E_1)}}\right)$