What is the value of 3f(x) when x is 6

1 answer:

8 0

It depends of wich function you are talking about:
For example, if $f(x)=x^2$ , just put $x=6$ into formula:

$f(6)=6^2=36$

And multiply by 3:

$3f(6)=108$

So, the answer is $3f(6)$ .

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Please anyone solve this for me..No spam.

Tamiku [17]

Answer:

3096

Step-by-step explanation:

Given:

$3x-\frac{1}{4y}=24$

Rewrite it as:

$3x=\frac{1}{4y}+24$
$x=\frac{1}{12y}+8$

Simplify the expression:

$8x(6x - \frac{1}{y} ) + \frac{1}{12y^2} (4 - 3y + 36xy^2) =$
$8(\frac{1}{12y}+8)(6(\frac{1}{12y}+8) - \frac{1}{y} ) + \frac{1}{3y^2} - \frac{1}{4y} + 3x =$
$8(\frac{1}{12y}+8)(48- \frac{1}{2y} ) + \frac{1}{3y^2} - \frac{1}{4y} + 24 + \frac{1}{4y} =$
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$8(384-\frac{1}{24y^2}) + \frac{1}{3y^2} + 24 =$
$8*384-\frac{1}{3y^2} + \frac{1}{3y^2} + 24 =$
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$3096$

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Fittoniya [83]

The circle equation is in the format (x – h)² + (y – k)² = r², with the center being at the point (h, k) and the radius being "r".

QUESTION 11.
Equation x²+y²+10x-14y-7 =0 can be rewritten as: x²+10x+25 + y² -14y + 49 -7 - 25 - 49=0
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QUESTION 13.
As there are missing information in the question, I can't assist. However, you can use the general circle equation (x – h)² + (y – k)² = r² to solve the question.

Finally equations 14 & 15 aren't linear.

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