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3 years ago

11

What is 8 multiplied by 4/7 as a mixed number

2 answers:

Eddi Din [679]3 years ago

6 0

Hey there!

"What is $8$ multiplied by $\frac{4}{7}$ as a mixed number?"

$\frac{8}{1} \times\frac{4}{7}$
$8(4)$ $= 32$
$1(7)$ $= 7$
$\boxed {Answer: \frac{32}{7} }$ ← (Improper fraction)
$\boxed{Answer: 4\frac{4}{7} }$ ← (mixed number/fraction)

Good luck on your assignment and enjoy your day!

~ $LoveYourselfFirst:)$

kondaur [170]3 years ago

4 0

Answer:

4 4/7

Step-by-step explanation:

8 * 4/7

32/7

7 goes into 32 4 times

4*7 =28

32-28 = 4 There are 4 left over. This goes over the denominator

4 4/7

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Answer:

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Step-by-step explanation:

We have been given that the concentration on hand is 10 mg per ml.

We know that gr stands for grains.

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$\frac{1}{4}\text{ gr}\times \frac{60\text{ mg}}{\text{ gr}}$

$\frac{1}{4}\times 60\text{ mg}$

$15\text{ mg}$

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$\frac{x}{15\text{ mg}}=\frac{\text{1 ml}}{10\text{ mg}}$

$\frac{x}{15\text{ mg}}*15\text{ mg}=\frac{\text{1 ml}}{10\text{ mg}}*15\text{ mg}$

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4 years ago

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ra1l [238]

Answer:

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Step-by-step explanation:

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3 years ago

It is 2021. What year is it 20 years before the next year that is a<br> perfect square?

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4 years ago

Bob and Anna are planning to meet for lunch at Sally's Restaurant, but they forgot to schedule a time. Bob and Anna are each goi

Viktor [21]

Answer:

The expected cost is $8.75

<em></em>

Step-by-step explanation:

Given

$Time = \{1pm, 2pm, 3pm, 4pm\}$

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$C_2 = \$10$ --- If Bob and Anna do not meet

Required

The expected cost of Bob's meal

First, we list out all possible time both Bob and Anna can select

We have:

$(Bob,Anna) = \{(1,1),(1,2),(1,3),(1,4),(2,1),(2,2),(2,3),(2,4),(3,1),(3,2),(3,3)$ $,(3,4),(4,1),(4,2),(4,3),(4,4)\}$

$n(Bob, Anna) = 16$

The outcome of them meeting at the same time is:

$Same\ Time = \{(1,1),(2,2),(3,3),(4,4)\}$

$n(Same\ Time) = 4$

The probability of them meeting at the same time is:

$Pr(Same\ Time) = \frac{n(Same\ Time)}{n(Bob,Anna)}$

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$Pr(Same\ Time) = \frac{1}{4}$

The outcome of them not meeting:

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$Pr(Different) = \frac{n(Different)}{n(Bob,Anna)}$

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The expected cost is then calculated as:

$Expected = C_1 * P(Same) + C_2 * P(Different)$

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Take LCM

$Expected = \frac{\$5+\$30}{4}$

$Expected = \frac{\$35}{4}$

$Expected = \$8.75$

<em>The expected cost is $8.75</em>

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Answer:

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Step-by-step explanation:

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3 years ago