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IgorLugansk [536]
2 years ago
7

How do I solve this problem Increased by 3. 2 4 5 7 10 11 X, find the X

Mathematics
1 answer:
vitfil [10]2 years ago
3 0

Answer:

36

Step-by-step explanation:

2+4+5+7+10+11=39

39-3

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I am doing math how many equivalent fractions are there for 4/5 explain
mote1985 [20]
4/5 ,8/10, 16/20,
You multiply both numbers with the same number.
For ex. 4×2=8 5×2=10 so we have 8/10
6 0
3 years ago
What is 1 2/3 multiple 2/3
Flauer [41]

Answer:

1\frac{1}{9}

Step-by-step explanation:

Given the following question:

1\frac{2}{3} \times\frac{2}{3}

In order to multiply the two, we have to convert the mixed number into a improper fraction and then multiply the numerator by the numerator, the denominator by the denominator.

1\frac{2}{3} =3\times1=3+2=\frac{5}{3}
\frac{5}{3} \times\frac{2}{3}
5\times2=10
3\times3=9
=\frac{10}{9}

<u>Convert the improper fraction into a mixed number:</u>

\frac{10}{9}
\frac{10}{9} =10\div9=1\frac{1}{9}
=1\frac{1}{9}

Your answer is "1 1/9."

Hope this helps.

7 0
2 years ago
Solve by factorization<br> 2x^2 + 3x -20 = 0
saul85 [17]

Answer:

x=2.5 or x=-4

Step-by-step explanation:

factorisation= factors:1, 2, 4, 5, 10, 20 (only the positive factors)

We will use the factors 4 and 5.

=(2x-5)(x+4)=0

2x-5=0   || x+4=0

2x=+5      || x=-4

x=2.5  or x=-4

4 0
2 years ago
Read 2 more answers
Pat sewed 200 tote bags in 4 hours at what rate did pat sew the tote bags
Alik [6]

Answer:

50 tote bags were sewed per hour

Step-by-step explanation:


6 0
3 years ago
How to find function definition area
insens350 [35]

Answer:Definition area"? Do you mean the "natural domain" of the function- the region in which the formula is defined? In order that a number have a square root that number must be non-zero.

Step-by-step explanation:Here, we must have x−1x≥0.

If x is positive, multiplying both sides by x we have x2−1=(x−1)(x+1)≥0. In order for that to be true, both x- 1 and x+ 1 must have the same sign: either x-1> 0 and x+ 1> 0 or x- 1< 0 and x+ 1< 0. The first pair of inequalities is true for x> 1 and the second for x< -1. Since "x is positive", we must have x> 1.

If x is negative, multiplying both sides by x we have x2−1=(x−1)(x+1)≥0. In order for that to be true, x- 1 and x+ 1 must have opposite signs: x+ 1> 0 and x- 1< 0 or x- 1<0 and x- 1> 0. The first pair is true for −1≤0≤1. The second pair are never both true. Since "x is negative" we must have −1≤x≤0.

Of course, we also cannot divide by 0 so x= 0 is not in the domain. The domain is the union of the two separate sets:{x|−1≤x<0}∪{x|x>1}.

Hope That Helps!

8 0
3 years ago
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