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2 years ago

12 2/6 converted to a mixed number

Mathematics

2 answers:

love history [14]2 years ago

7 0

You probaly mean improper fraction. If it is the answer is 37/3

Kipish [7]2 years ago

3 0

12 2/6 is a mixed number. Though, it can be simplified to 12 1/3

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Everyone needs to get off of social and help us -_-

JulsSmile [24]

(x+2)(x+8)(x+k)=x^3+9x^2+6x-16

(x^2+10x+16)(x+k)=x^3+9x^2+6x-16

x^3+10x^2+16x+kx^2+10kx+16k=x^3+9x^2+6x-16

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7 0

2 years ago

9/25 ddivided by 729/1000

Nat2105 [25]

Kindly refer to attachment for solution.

Hope it helps ^_^

5 0

3 years ago

Read 2 more answers

There is a population of 15,500 bacteria in a colony. If the number of bacteria doubles every 234 hours, what will

saveliy_v [14]

Answer:

2,48,000

Step-by-step explanation:

Initial population of bacteria = 15,500

Bacteria doubles after every 234 hours

So, after 0 (zero) hours, no of bacteria = 15,500

After 234 hours, no. of bacteria = 2(15,500) = 31,000

After 468 hours, no. of bacteria = 2(31,000) = 62,000 (2*234 = 468)

After 702 hours, no. of bacteria = 2(62,000) = 124,000 (3*234 = 702)

After 936 hours, no. of bacteria = 2(124000) = 2,48,000 (4*234 = 936)

3 0

1 year ago

A number when divided by 32 gives the quotient 150 and remainder 5, find thenumber (dividend).

insens350 [35]

Answer:

4805=32×150 +5

Step-by-step explanation:

Dividend = Divisor × Quotient + Remainder

Here

Divisor is 32

Quotient is 150 and remainder is 5

3 0

2 years ago

Who can help me d e f thanks

12345 [234]

$y = (2ax^2 + c)^2 (bx^2 - cx)^{-1}$

Product rule:

$y' = \bigg((2ax^2+c)^2\bigg)' (bx^2-cx)^{-1} + (2ax^2+c)^2 \bigg((bx^2-cx)^{-1}\bigg)'$

Chain and power rules:

$y' = 2(2ax^2+c)\bigg(2ax^2+c\bigg)' (bx^2-cx)^{-1} - (2ax^2+c)^2 (bx^2-cx)^{-2} \bigg(bx^2-cx\bigg)'$

Power rule:

$y' = 2(2ax^2+c)(4ax) (bx^2-cx)^{-1} - (2ax^2+c)^2 (bx^2-cx)^{-2} (2bx - c)$

Now simplify.

$y' = \dfrac{8ax (2ax^2+c)}{bx^2 - cx} - \dfrac{(2ax^2+c)^2 (2bx-c)}{(bx^2-cx)^2}$

$y' = \dfrac{8ax (2ax^2+c) (bx^2 - cx) - (2ax^2+c)^2 (2bx-c)}{(bx^2-cx)^2}$

$y = \dfrac{3bx + ac}{\sqrt{ax}}$

Quotient rule:

$y' = \dfrac{\bigg(3bx+ac\bigg)' \sqrt{ax} - (3bx+ac) \bigg(\sqrt{ax}\bigg)'}{\left(\sqrt{ax}\right)^2}$

$y'= \dfrac{\bigg(3bx+ac\bigg)' \sqrt{ax} - (3bx+ac) \bigg(\sqrt{ax}\bigg)'}{ax}$

Power rule:

$y' = \dfrac{3b \sqrt{ax} - (3bx+ac) \left(-\frac12 \sqrt a \, x^{-1/2}\right)}{ax}$

Now simplify.

$y' = \dfrac{3b \sqrt a \, x^{1/2} + \frac{\sqrt a}2 (3bx+ac) x^{-1/2}}{ax}$

$y' = \dfrac{6bx + 3bx+ac}{2\sqrt a\, x^{3/2}}$

$y' = \dfrac{9bx+ac}{2\sqrt a\, x^{3/2}}$

$y = \sin^2(ax+b)$

Chain rule:

$y' = 2 \sin(ax+b) \bigg(\sin(ax+b)\bigg)'$

$y' = 2 \sin(ax+b) \cos(ax+b) \bigg(ax+b\bigg)'$

$y' = 2a \sin(ax+b) \cos(ax+b)$

We can further simplify this to

$y' = a \sin(2(ax+b))$

using the double angle identity for sine.

7 0

1 year ago