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Leto [7]
3 years ago
14

What Is the slope line through (1,-1) and (5,-7)

Mathematics
2 answers:
lesantik [10]3 years ago
5 0
The answer is c on enguity
Ksenya-84 [330]3 years ago
4 0
Your slope should be 3/2
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20 point Which of the following is a solution of x2 + 4x + 25? (1 point)
Dafna11 [192]
2 + I square root of 21
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Can someone pls help me on the last three!
Solnce55 [7]
Red to total I believe is 12/23
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3 years ago
(2n – 3)(5n+6)<br> How do I solve this ?
nalin [4]

Answer:

Step-by-step explanation:

(2n - 3)(5n + 6) = 2n*(5n + 6) -3*(5n +6)

=2n*5n + 2n*6 -3*5n + (-3)*6

=10n² + 12n - 15n - 18

= 10n² -3n - 18

5 0
3 years ago
Read 2 more answers
Identify the law illustrated by: 5n x 1 is the same as 5n
tangare [24]

<u><em>The law illustrated is Distributive Law</em></u>

This question is under a topic called algebra laws.

The laws are;

- Commutative law; This implies that when we are to add or multiply numbers, the order of addition or multiplication doesn't matter as we will still get same result.

- Associative law; This implies that if we want to add more than 2 numbers, if we decide to add the first 2 before adding the third one, we will still get the same result as if we added the second one to the third one before adding to the first one. This law also applies to multiplication.

- Distributive law; This implies that when two numbers are multiplied to produce a result, both numbers are factors of the result.

We are told in the question that ; 5n x 1 = 5n

This means that 5n and 1 are factors of 5n and this corresponds to distributive law

Read more at; brainly.in/question/39479409?tbs_match=1

7 0
2 years ago
A population has a standard deviation of 5.5. What is the standard error of the sampling distribution if the sample size is 81?
VladimirAG [237]

Answer:

\sigma = 5.5

And we have a sample size of n =81. We want to estimate the standard error of the sampling distribution \bar X and for this case we know that the distribution is given by:

\bar X \sim N(\mu ,\frac{\sigma}{\sqrt{n}})

And the standard error would be:

\sigma_{\bar x}= \frac{\sigma}{\sqrt{n}}

And replacing we got:

\sigma_{\bar x}=\frac{5.5}{\sqrt{81}}= 0.611

Step-by-step explanation:

For this case we know the population deviation given by:

\sigma = 5.5

And we have a sample size of n =81. We want to estimate the standard error of the sampling distribution \bar X and for this case we know that the distribution is given by:

\bar X \sim N(\mu ,\frac{\sigma}{\sqrt{n}})

And the standard error would be:

\sigma_{\bar x}= \frac{\sigma}{\sqrt{n}}

And replacing we got:

\sigma_{\bar x}=\frac{5.5}{\sqrt{81}}= 0.611

4 0
3 years ago
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