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3 years ago

What Is the slope line through (1,-1) and (5,-7)

Mathematics

2 answers:

lesantik [10]3 years ago

5 0

The answer is c on enguity

Ksenya-84 [330]3 years ago

4 0

Your slope should be 3/2

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I need help with this problemmm, someone help mee!!.

Varvara68 [4.7K]

Answer:

∠A=30°

Step-by-step explanation:

let's call the angle at the bottom B and the one next to the 130 C

∠A=3x-6

∠C=180-130= 50°

vertical angles are equal∠B =8x+4

∠A+∠C+∠B=180°

find x:

3x-6+50+8x+4= 180°

11x+48=180°

11x= 132

x=12

find ∠A

∠A=3x-6= 3(12)-6 =30°

5 0

3 years ago

Help- ASAP please (25 points)

Alina [70]

Answer:

(t^2 -4) (t^2 +4)

(t-2)(t+2)(t^2+4)

Step-by-step explanation:

t^4 - 16

We can write this as the difference of squares

We know the dfference of squares is

(a^2 - b^2) = (a-b) (a+b)

( t^2 ^2 - 4^2) = (t^2 -4) (t^2 +4)

We can write t^2 -4 as the difference of squares

t^2 -4 = t^2 -2^2 = (t-2)(t+2)

Replacing this in

( t^2 ^2 - 4^2) = (t^2 -4) (t^2 +4) = (t-2)(t+2)(t^2+4)

8 0

3 years ago

Read 2 more answers

Need help ASAP will mark brainliest

nalin [4]

Answer:

5x -7y = 21

Step-by-step explanation:

A sketch can convince you that BC is a transversal perpendicular to parallel lines AB and CD. The question asks for an equation for CD, so we just need to write the equation of a line through D that is parallel to AB.

One way to do this is to equate the slopes of the parallel lines:

∆y/∆x for AB = ∆y/∆x for CD

(y2 -y1)/(x2 -x1) = (y -2)/(x -7) . . . . . . where (x1, y1) = A; (x2, y2) = B; (7, 2) = D

(4 -(-1))/(1 -(-6)) = (y -2)/(x -7)

5(x -7) = 7(y -2) . . . . . . . . . . . . . cross multiply

5x -7y = 21 . . . . . . . . . . . . . . . . add 35 -7y, simplify

_____

Note that the graph shows the line CD is named "b", and its equation is shown at upper left. Multiplying that equation by -1 gives the one shown here.