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Stella [2.4K]
3 years ago
8

(x+3)(x-2) Polynomial in standard form

Mathematics
2 answers:
postnew [5]3 years ago
7 0
You FOIL the binomials out to get a quadratic.
omeli [17]3 years ago
5 0
The answer is x^2 + x - 6 =0
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Regular hexagon ABCDEF is inscribed in circle X and has an apothem that is 6√3 inches long. Use the length of the apothem to cal
Phantasy [73]

Answer:

Part A

The \ circumradius, \  R = \dfrac{a}{cos \left(\dfrac{\pi}{n} \right)}

Plugging in the given values we get;

The \ circumradius, \  R = \dfrac{6 \cdot \sqrt{3} }{cos \left(\dfrac{\pi}{6} \right)} = \dfrac{6 \cdot \sqrt{3} }{\left(\dfrac{\sqrt{3} }{2} \right)} = 6 \cdot \sqrt{3}  \times \dfrac{2}{\sqrt{3} }  = 12

R = 12 inches

The radius of the circumscribing circle is 12 inches

Part B

The length of each side of the hexagon, 's', is;

s = a \times 2 \times tan \left(\dfrac{\pi}{n} \right)

Therefore;

s = 6 \cdot \sqrt{3}  \times 2 \times tan \left(\dfrac{\pi}{6} \right) = 6 \cdot \sqrt{3}  \times 2 \times \left(\dfrac{1}{\sqrt{3} } \right) = 12

s = 12 inches

The perimeter, P = n × s = 6 × 12 = 72 inches

The perimeter of the hexagon is 72 inches

Step-by-step explanation:

The given parameters of the regular hexagon are;

The length of the apothem of the regular hexagon, a = 6·√3 inches

The relationship between the apothem, 'a', and the circumradius, 'R', is given as follows;

a = R \cdot cos \left(\dfrac{\pi}{n} \right)

Where;

n = The number of sides of the regular polygon = 6 for a hexagon

'a = 6·√3 inches', and 'R' are the apothem and the circumradius respectively;

Part A

Therefore, we have;

The \ circumradius, \  R = \dfrac{a}{cos \left(\dfrac{\pi}{n} \right)}

Plugging in the values gives;

The \ circumradius, \  R = \dfrac{6 \cdot \sqrt{3} }{cos \left(\dfrac{\pi}{6} \right)} = \dfrac{6 \cdot \sqrt{3} }{\left(\dfrac{\sqrt{3} }{2} \right)} = 6 \cdot \sqrt{3}  \times \dfrac{2}{\sqrt{3} }  = 12

The circumradius, R = 12 inches

Part B

The length of each side of the hexagon, 's', is given as follows;

s = a \times 2 \times tan \left(\dfrac{\pi}{n} \right)

Therefore, we get;

s = 6 \cdot \sqrt{3}  \times 2 \times tan \left(\dfrac{\pi}{6} \right) = 6 \cdot \sqrt{3}  \times 2 \times \left(\dfrac{1}{\sqrt{3} } \right) = 12

The length of each side of the hexagon, s = 12 inches

The perimeter of the hexagon, P = n × s = 6 × 12 = 72 inches

The perimeter of the hexagon = 72 inches

5 0
2 years ago
Suppose a line has slope -2/3 and passes through the point (1, 8). which other point must also be on the graph?
Arisa [49]
<h3>Answer:   Choice A.   (7,4)</h3>

============================================

Explanation:

Use the slope and given point to find the y intercept

y = mx+b

8 = (-2/3)*(1) + b

8 = -2/3 + b

8 + 2/3 = b

24/3 + 2/3 = b

26/3 = b

b = 26/3

The equation of the line is y = (-2/3)x + 26/3

To confirm this, plug in x = 1 and we should get y = 8, due to the point (1,8)

y = (-2/3)x + 26/3

y = (-2/3)*1 + 26/3

y = -2/3 + 26/3

y = (-2+26)/3

y = 24/3

y = 8

So that verifies we have the correct equation.

--------------

Next, go through each answer choice to see if the x coordinate of the point leads to the y coordinate.

If we try x = 7, then,

y = (-2/3)x + 26/3

y = (-2/3)(7) + 26/3

y = -14/3 + 26/3

y = (-14+26)/3

y = 12/3

y = 4

This shows that (7,4) is on the line. Choice A is the answer

That rules out choice B.

----------------

If we tried x = -5, then,

y = (-2/3)x + 26/3

y = (-2/3)(-5) + 26/3

y = 10/3 + 26/3

y = 36/3

y = 12

meaning that (-5,12) is on the line. That rules out choices C and D.

Refer to the graph below. It visually confirms that of the four answer choices, only point A is on the line. I used GeoGebra to make the graph.

5 0
2 years ago
Somebody help me with this
den301095 [7]

4x^2-5x=0

x (4x+5)=0

either. or

x=0. 4x= -5

x = -5/4

5 0
3 years ago
Read 2 more answers
4.4674 divided by 0.18 please help!
sergejj [24]

Answer:

24.8188888889


Step-by-step explanation:

4.4674/0.18=24.8188888889

8 0
2 years ago
2t+8 &gt; -4 (t+1)<br> THE &gt; HAS A LIL LINE UNDER IT :)<br> &gt; = ____<br> _
lara31 [8.8K]
2t + 8 ≥ -4(t+1)

PEMDAS

2t + 8 ≥ -4t - 4

2t + 12 ≥ -4t

12 ≥ -6t

-2 ≤ t
7 0
3 years ago
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