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DIA [1.3K]
2 years ago
5

A man divided $9,000 among his wife, son, and daughter. The wife received twice as much as the daughter, and the son received $1

,000 more than the daughter. How much did each receive?
Mathematics
1 answer:
mestny [16]2 years ago
7 0

Answer:4000

Step-by-step explanation: becuase each would get 3000 and he got 1000 so 3000+1000=4000

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It is four/4 I believe D.4

Step-by-step explanation:

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3 years ago
Write a real-world problem that can be represented by a rule and a table using division
LuckyWell [14K]
A company makes different size square containers. How can you find the length of each side if you know the perimeter of each of the containers? Represent your answer in a table, and right and equation that shows the rule used. You would write the equation x/4=y. I would create an input/output table with the labels x and y. I would then write various lengths for the perimeters and use the rule of dividing by 4 to find the y values.
4 0
3 years ago
What is the median of the following set? 28, 45, 12, 34, 36, 45, 19, 20
amm1812

Answer:

its 31

Step-by-step explanation:

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5 0
3 years ago
Help!! This doesn't make any sense to me. Can anyone help me solve for the value of x?
notsponge [240]
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9x = 5x + 9 + x

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9x = 6x + 9

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3x = 9

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6 0
3 years ago
Suppose that a poll taken 10 years ago found that 55​% of parents spank their children. Suppose a recent poll of 500 adults with
Kryger [21]

Answer:

Of the 500 parents surveyed 275 would be expected to spank their​ children.

Step-by-step explanation:

Let the random variable <em>X </em>represent the number of parents who spank their children.

It is provided that, from previous studies, <em>p</em> = 55​% of parents spank their children.

A random sample of <em>n</em> = 500 adults were selected.

The event whether a parent spank their children is independent of other parents.

The random variable <em>X </em>thus follows a Binomial distribution with parameters <em>n</em> = 500 and <em>p</em> = 0.55.

The expected value of a Binomial random variable is:

E(X)=np

         =500\times 0.55\\=275

Thus, of the 500 parents surveyed 275 would be expected to spank their​ children.

6 0
3 years ago
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