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3 years ago

Which is the solution to -2(8x-4)<2x+5 x>1/6 x<1/6. X>6 x<6

Mathematics

2 answers:

Yuri [45]3 years ago

8 0

Answer:

Step-by-step explanation:

-2(8x-4)<2x+5

We open the brackets first

-16X + 8 < 2X + 5

Combine the like terms, we subtract 8 on both sides

-16x + 8 -8 < 2x +5 -8

-16 x < 2x -3

We subtract 2x on both side

-16x -2x < -3

-18 x < -3

simplify, by dividing both side by -18,

-18x/-18 <-3/18

x > 1/6 (reverse the sign to >)

raketka [301]3 years ago

3 0

Answer:

Choice A is correct answer.

Step-by-step explanation:

Given inequalities is:

-2(8x-4) < 2x+5

We have to find the value of x.

-16x+8 < 2x+5

Adding 16x to both sides of inequalities , we get

16x-16x+8 < 16x+2x+5

0+8 < 18x+5

Adding -5 to both sides of inequality ,we get

-5+8 < 18x+5-5

3 < 18x

Multiplying by 1/18 to both sides of above equation,we get

1/18(3) < 1/18(18xx)

3/18 < x

Swapping sides,we get

x > 3/18

x > 1/6 which is the answer.

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Answer:

A) The fraction of sum of money did each child receive is $\frac{3 x}{16}$

B) The sum of money did Jeff have $ 3200

Step-by-step explanation:

Given as :

Let The sum of money did Jeff have = $ x

The fraction of money did Jeff's wife get = $\frac{1}{4}$ of $ x

The remaining money Jeff will have = $ x - $\frac{1}{4}$ of $ x

I.e The remaining money Jeff will have = $\frac{4 x - x}{4}$

= $\frac{3 x}{4}$

A ) The remaining amount of money is divided equally among 4 children

So, The fraction of sum of money did each child receive = $\frac{\frac{3 x}{4}}{4}$

I.e The fraction of sum of money did each child receive = $\frac{3 x}{16}$

B ) If each child will receive $ 600

∴, $\frac{3 x}{16}$ = $ 600

Or, 3 x = $ 600 × 16

Or, 3 x = $ 9600

∴ x = $\frac{9600}{3}$

I.e x = $ 3200

So, The sum of money did Jeff have $ 3200

Hence ,

A) The fraction of sum of money did each child receive is $\frac{3 x}{16}$

B) The sum of money did Jeff have $ 3200 Answer

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3 years ago

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Answer:

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Step-by-step explanation:

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3 years ago

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Answer:

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Step-by-step explanation:

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Area of a square: S^2

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