If you're supposed to find the measure of the arc:
The minor arc CD has the same measure as the central angle it subtends. In this case, arc CD has measure 50º. In radians, that's
50º * (π/180 rad/º) = 5π/18 rad
If you instead meant to ask about finding the length of the arc CD, recall that arc lengths and their subtended central angles occur in a fixed ratio equal to the ratio of the circle's total circumference to 2π rad. In other words, if <em>L</em> is the length of the minor arc CD, then
<em>L</em> /(5π/18 rad) = 2π (7 cm) / (2π rad)
==> <em>L</em> = 35π/18 cm
(Notice that arc measure is given radians, while arc length is given in cm, which is why I offer two different answers here.)
The diagonal WY bisects the diagonal XV at point D, which means that XV is divided into two equal line segments XD and XV.
Replace the equation above with the given expressions for both line segments:
XD= 2x-6
XV= 3x-6
