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MrRa [10]
3 years ago
15

Is 93 divisible by 3 . True or false

Mathematics
2 answers:
pishuonlain [190]3 years ago
7 0
True, as 93 divided by 3 is 31; a whole number :)
Yuliya22 [10]3 years ago
4 0

Answer:

93 is also divisible by 3 (true).

Step-by-step explanation:

Given : 93 divisible by 3.

To find : Is 93 divisible by 3 . True or false.

Solution : We have given  93 divisible by 3.

By the divisibility rule:

If the sum of the digit of a given number is divisible by 3  then the given number must be divisible by 3 .

Example : 81

8+1 =9 that is divisibility by 3 so the 81 is also divisible by 3.

Now , 93 = 9+3 =12.

As we know 12 is divisible by 3.

So , 93 is also divisible by 3.

Therefore, 93 is also divisible by 3 (true).

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Lostsunrise [7]

Answer:

Hope this helps

Step-by-step explanation: Number 81 decreased by 7% (7 percent) of its value (percentage decrease) and calculated absolute change (actual difference). Answer: percentage decreased number = 75.33, absolute change (actual difference) = -5.67

8 0
2 years ago
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Lucy’s house is located at the point shown on the coordinate grid. Ainsley’s house is located 2 units right and 3 units down fro
dybincka [34]

Answer: 3,3

Step-by-step explanation:

5 0
2 years ago
(CO 4) In a sample of 8 high school students, they spent an average of 24.8 hours each week doing sports with a sample standard
AveGali [126]

Answer:  

(22.12, 27.48)

Step-by-step explanation:

Given : Significance level : \alpha: 1-0.95=0.05

Sample size : n= 8 , which is a small sample (n<30), so we use t-test.

Critical values using t-distribution: t_{n-1,\alpha/2}=t_{7,0.025}=2.365

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Standard deviation : \sigma=3.2\text{ hours}

The confidence interval for population means is given by :-

\overline{x}\pm t_{n-1,\alpha/2}\dfrac{\sigma}{\sqrt{n}}

i.e. 24.8\pm(2.365)\dfrac{3.2}{\sqrt{8}}

24.8\pm2.67569206001\\\\\approx24.8\pm2.68\\\\=(24.8-2.68, 24.8+2.68)=(22.12, 27.48)

Hence, the 95% confidence interval, assuming the times are normally distributed.=  (22.12, 27.48)

6 0
2 years ago
Please help Evaluate the expression. (7 – 4)[(5 +
IgorLugansk [536]
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3 years ago
Evaluate the given integral by changing to polar coordinates. sin(x2 y2) dA R , where R is the region in the first quadrant betw
alexira [117]

Answer:

I = 1.47001

Step-by-step explanation:

we have the function

f(x,y)=sin(x^2y^2)\\

In polar coordinates we have

x=rcos\theta\\y=rsin\theta

and dA is given by

dA=rdrd\theta

Hence, the integral that we have to solve is

I=\int \limt_2^4 \int \limit_0^{\pi /2}sin(r^4cos^2\theta sin^2\theta)rdrd\theta

This integral can be solved in a convenient program of your choice (it is very difficult to solve in an analytical way, I use Wolfram Alpha on line)

I = 1.47001

Hope this helps!!!

7 0
3 years ago
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